No. A mirror works because of reflection.
What happens is the potential value of the conductor decreases due to the presence of second conductor
as the capacitance is given by C = q/v
the value of v deceases as v-v1
thus the new capacitance is = C' = q/v-v1 thus the lowering of v increases the capacitance
Explanation:
sinces : Momentum = velocity × mass
then : 30 = 10 × m and m = 30 ÷ 10 = 3 kg
Given data;
Fn = 10 N
Fs = 7 N
Fe = 4 N
force in X direction (Fx) = 4 N
force in Y direction (Fy) = 10-7 = 3 N
Net force (Fnet) = Sq.root[(Fx)² + (Fy)²]
= Sq root [ 4² + 3² ]
= 25 N
<em> Net force acting = 25 N</em>
Explanation :
There are two types of collision i.e. elastic and elastic collision.
- Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
- Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.
From Newton's second law,
F = m a
a is the rate of change of velocity.

There is a inverse relation between the force and the time of collision.
The change in <em><u>momentum</u></em> will remain the same during a collision, the force needed to bring an object to a stop can be <em><u>increased</u></em> if the time of the collision is <u><em>decreased</em></u>.