Answer:
Step-by-step explanation:
The growth factor is 1.06.
The year is 2020 - 1978 = 42.
This is exponential growth as the growth factor is > 1.
The equation is V = 40000(1.06)^42
V works out to $462,281
Compute the differential for both sides:
4<em>y</em> - 3<em>xy</em> + 8<em>x</em> = 0
→ 4 d<em>y</em> - 3 (<em>y</em> d<em>x</em> + <em>x</em> d<em>y</em>) + 8 d<em>x</em> = 0
Solve for d<em>y</em> :
4 d<em>y</em> - 3<em>y</em> d<em>x</em> - 3<em>x</em> d<em>y</em> + 8 d<em>x</em> = 0
(4 - 3<em>x</em>) d<em>y</em> + (8 - 3<em>y</em>) d<em>x</em> = 0
When <em>x</em> = 0, we have
4<em>y</em> - 3•0<em>y</em> + 8•0 = 0 → 4<em>y</em> = 0 → <em>y</em> = 0
and with d<em>x</em> = 0.05, we get
(4 - 3•0) d<em>y</em> + (8 - 3•0) • 0.05 = 0
→ 4 d<em>y</em> + 0.4 = 0
→ 4 d<em>y</em> = -0.4
→ d<em>y</em> = -0.1
Answer:
The amount the car will be worth after 6 years is £21,917 and 22 pence
Step-by-step explanation:
The amount for which Colin buys the car, PV = £28,100
The amount by which the car depreciates each year, r = 4%
The number of years after which the value of the car is sought, n = 6 years
The future value, FV, based on an annual depreciation is given as follows;
Substituting the known values gives;
Therefore, the amount the car will be worth after 6 years, future value FV₆ = £21,917 and 22 pence
Answer:
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Answer:
110
Step-by-step explanation:
Let the three numbers be 100, 110 and 120
100 + 110 + 120 = 330
Total numbers = 3
