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2 years ago

PLEASE HELP!! WILL GIVE BRAINLIEST!!!!

Mathematics

1 answer:

Arturiano [62]2 years ago

5 0

Answer:

y=1

Step-by-step explanation:

Given function y=m(x)

The question is to find the y value where x equals -2 so the easiest way is to plus x=-2 in the graph, we can get y=1.

Hopefully this helps, if you have any questions please feel free to ask them in the comment section below, I'll be more than happy to answer!

You might be interested in

What is the volume of a cylinder with base radius 4 and height 5?

Vsevolod [243]

Answer:

251.2 unit²

Step-by-step explanation:

Radius = 4 unit, height = 5 unit

Volume of cylinder = pi r² h

Where pi(#) = 3.14

Volume = # × 4² × 5

Volume = # × 16 × 5

Volume = 80# unit²

Volume = 80 × 3.14

Volume = 251.2 unit²

I hope this was helpful, please rate as brainliest

5 0

2 years ago

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0

2 years ago

IF YOU ANSWER IN !) SECONDS ILL GIVE YOU 100 POINTS

Semmy [17]

Ummm hi :) Ann’s Kama abs

5 0

2 years ago

20) Find x if KLE = 28°, KLM= 118x,

qaws [65]

B is the answer i’m pretty sure

7 0

2 years ago

Read 2 more answers

20 Points!! Please help

Setler79 [48]

Answer:

The graph of the triangle LMN and the image L'M'N' created by rotation of ΔLMN through 180° made with MS Excel is attached

The transformation involved in the 180° rotation of ΔLMN to create ΔL'M'N' includes;

The changing of the signs of the x and y-values of the coordinates of the vertices ΔLMN to get the corresponding x and y-values of the coordinates of the vertices of ΔL'M'N' as follows;

Before, rotation

The coordinates of the vertices of ΔLMN are; L(3, 3), M(9, 9), and N(9, 3)

After 180° rotation

The coordinates of the vertices of the image of ΔLMN, which is ΔL'M'N' are; L'(-3, -3), M'(-9, -9), and N'(-9, -3)

Therefore, the image of ΔLMN, ΔL'M'N' is located in the third quadrant, while the preimage ΔLMN is in the first quadrant

Part B

The lines drawn through L and L' and through M and M' are colinear lines

Part C

The lines dawn through points N and N' will not pass through the same line as the lines through L and L' and through M and M', because the three points are not colinear

Step-by-step explanation:

8 0

2 years ago