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3 years ago

Please help me ! geometry help greatly needed. asap if possible.

Mathematics

2 answers:

Ugo [173]3 years ago

7 0

Answer:

b)52

Step-by-step explanation:

360-120-136=104

104%2=52

crimeas [40]3 years ago

7 0

Answer:

Step-by-step explanation:

not A sry

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Two sides of a triangle measure 9 cm and 23 cm what could be the measurement of the third side of the triangle

Vladimir79 [104]

Pythagorean Theorem: a^2+b^2=c^2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
$\sqrt{448}$
b = 21.2

6 0

3 years ago

5(x−3) 2 +4=<br> answer plz

Kryger [21]

Answer:

The answer is 10x-26 or try using the Distributive Property.

Step-by-step explanation:

8 0

3 years ago

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Emerson deposited $194 into the bank. What will the balance be if Emerson left the money there for 7 years with an interest rate

SOVA2 [1]

Answer:

You just have to round to the cent place to get your answer

Step-by-step explanation:

Hope it helped!

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4 0

3 years ago

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A boy scout troop is selling Christmas trees at a local tree lot. In the morning, they sold 20 Douglas Fir trees and 23 Noble Fi

Katarina [22]

Answer:

The cost of 1 Douglas Fir Tree = $30

The cost of 1 Noble Fir Tree = $ 79

Step-by-step explanation:

Let the cost of 1 Douglas Fir tree = $ x

Let the cost of 1 Noble Fir tree = $ y

Total Amount Earned in morning = $2,417

Total Amount Earned in evening = $2,022

Now, according to the question:

20 x + 23 y = 2417

and 20 x + 18 y = 2022

Subtraction both equation , we get

20 x + 23 y - (20 x + 23 y) = 2417 - 2022

or, 20x - 20x + 23 y - 18 y = 395

or, 5 y = 395

⇒ y = 395 / 5 = 79

Hence, the cost of 1 Noble Fir Tree = $ 79

Now, put the value of y in 20 x + 23 y = 2417 , we get

20x + 23(79) = 2417

or, 20x = 2417 - 1817 = 600

or, x = 600/20 = 30

Hence, the cost of 1 Douglas Fir Tree = $30

7 0

3 years ago

Suppose that textbook weights are normally distributed. You measure 33 textbooks' weights, and find they have a mean weight of 7

AleksAgata [21]

Answer:

$75-2.58\frac{13.3}{\sqrt{33}}=69.027$

$75+2.58\frac{13.3}{\sqrt{33}}=80.793$

And the 95% confidence interval would be between (69.027;80.793)

Step-by-step explanation:

Information given

$\bar X=75$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=13.3$ represent the population standard deviation

n=33 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=33-1=32$

The Confidence level is 0.99 or 99%, the significance would be $\alpha=0.01$ and $\alpha/2 =0.005$ , the critical value for this case would be $z_{\alpha/2}=2.58$

And replacing we got:

$75-2.58\frac{13.3}{\sqrt{33}}=69.027$

$75+2.58\frac{13.3}{\sqrt{33}}=80.793$

And the 95% confidence interval would be between (69.027;80.793)

6 0

3 years ago