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Marysya12 [62]
2 years ago
6

Find the equation of the line that passes through (3,1) and is parallel to y=2x+3

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
7 0

Answer:

  y -1 = 2(x -3)

Step-by-step explanation:

The given equation is in slope-intercept form:

  y = mx +b . . . . line with slope m and y-intercept b

  y = 2x +3 . . . . . line with slope 2 and y-intercept 3

__

A parallel line will have the same slope. Since you are given a point, it is convenient to use the point-slope form for the equation you want:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

  y -1 = 2(x -3) . . . . . . line with slope 2 through point (3, 1)

__

<em>Additional comment</em>

If you want the slope-intercept form you can solve for y:

  y = 2(x -3) +1 = 2x -6 +1

  y = 2x -5 . . . . . slope-intercept form of the parallel line

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Answer:

y=-1/2x-5

Step-by-step explanation:

Well we know that the slope is -1/2 so we can write the equation like this:

y=-1/2x+b (This is because of y=mx+b) (m is slope) (b is y-intercept)

Now we can replace the y and x with -4 and -3 because of (x,y). (-4,-3) x is -4 and y is -3

-3=-1/2(-4)+b

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Subtract 2 on both side:

-2-3=2-2+b

-5=b

Answer:

y=-1/2x-5

Hope this helps!

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Step-by-step explanation: idk

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Answer:

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Step-by-step explanation:

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