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Kisachek [45]
3 years ago
10

Find the force in free space between two like point charges of one coulomb each placed one metre apart

Physics
1 answer:
Umnica [9.8K]3 years ago
3 0

Explanation:

{ \rm{force =  \frac{q _{1}q _{2} }{4\pi \phi \:   {r}^{2} } }} \\

  • q is charge
  • 4πQ is 1 / (9 × 10^9)
  • r is separation distance

{ \rm{force =  \frac{1 \times 1 \times 9 \times  {10}^{9} }{ {1}^{2} } }} \\  \\ { \boxed{ \rm{force = 9 \times  {10}^{9} \: newtons }}}

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Two astronauts are floating close to each other in space. Can they talk to each other without using any special device? plsss he
storchak [24]

Answer:

no they can't talk to each other bcoz of the lack of atmosphere.

Explanation:

l hope it helps you

5 0
3 years ago
A water wave traves with a length of 10 meters and a frequency of 30 hertz, what is the velocity of the wave?
UNO [17]

Answer: 300 m/s

Explanation:

Given that:

length of water wave (λ) = 10 metres

Frequency of water wave (F) = 30 Hertz

Velocity of water wave (V) = ?

The velocity of a wave is the distance covered by the wave in one second. It is measured in metre per second, and represented by the symbol V. It is related to frequency and wave length by the formula: V = F λ

V = 30 Hertz x 10 metres

V = 300 m/s

Thus, the velocity of the water wave is 300 m/s

4 0
3 years ago
The Kelly family and the Garcia family each used their sprinklers last summer. The water output rate for the Kelly family's spri
elena55 [62]

Answer:

30 hours

15 hours.

Explanation:

Let the Kelly used sprinkler for t hours and Gracia used the sprinkler for the rest ie (45 - t) hours .

Water output by Kelly = (35 x t) L

Water output by Gracia = 20 ( 45 - t ) L

Total output = 35t + 20(45 - t)

So,  35 t + 20 (45 - t ) = 1350

35 t + 900 - 20 t = 1350

15 t = 450

t = 30 hours

So Kelly used sprinkler for 30 hours and Gracia used it for 45 - 30 = 15 hours.

3 0
3 years ago
(i) a force of 35.0 n is required to start a 6.0-kg box moving across a horizontal concrete floor, (a) what is the coefficient o
Serjik [45]

a. The force applied would be equal to the frictional force.

F = us Fn

where, F = applied force = 35 N, us = coeff of static friction, Fn = normal force = weight

 

35 N = us * (6 kg * 9.81 m/s^2)

us = 0.595

 

b. The force applied would now be the sum of the frictional force and force due to acceleration

F = uk Fn + m a

where, uk = coeff of kinetic friction

 

35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)

uk = 0.533

4 0
3 years ago
How does weak background radiation coming from every direction in the sky support the big bang theory
postnew [5]

Answer:

Option 1

It provides evidence of universe expansion

Explanation:

The Big Bang Theory actually explains the universe as originating from a single point, which expanded as billions of years went by.

The background radiation supports this theory in the sense that if the universe is expanding, this means that the universe is cooling and continuously losing heat, which results in background radiation

3 0
3 years ago
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