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Kisachek [45]
3 years ago
10

Find the force in free space between two like point charges of one coulomb each placed one metre apart

Physics
1 answer:
Umnica [9.8K]3 years ago
3 0

Explanation:

{ \rm{force =  \frac{q _{1}q _{2} }{4\pi \phi \:   {r}^{2} } }} \\

  • q is charge
  • 4πQ is 1 / (9 × 10^9)
  • r is separation distance

{ \rm{force =  \frac{1 \times 1 \times 9 \times  {10}^{9} }{ {1}^{2} } }} \\  \\ { \boxed{ \rm{force = 9 \times  {10}^{9} \: newtons }}}

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4 years ago
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3 years ago
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umka2103 [35]

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3 0
3 years ago
Read 2 more answers
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Answer:

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Explanation:

7 0
2 years ago
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postnew [5]

Answer:

Option 1

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3 0
3 years ago
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