Answer:
a.) 490m
b.) 98m/s
Explanation:
Given that the
Acceleration g = 9.8 m/s^2
Time = 10s
Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,
U = 0
Distance covered = height H
The height can be calculated by using second equation of motion
H = Ut + 1/2gt^2
Substitute g and t into the formula
H = 1/2 × 9.8 × 10^2
H = 490 m
Therefore, she travels as far as 490 m
b.) Her final velocity can be calculated by using third equation of motion
V^2 = U^2 + 2gH
Substitute g and H into the formula.
Remember that U = 0
V^2 = 2 × 9.8 × 490
V^2 = 9604
V = sqrt (9604)
V = 98 m/s
Therefore, her final velocity is 98 m/s
Answer:
31-40 m/s
Explanation:
The kinetic energy of an object is given by :
m is mass of the object
v is velocity
If mass of an object is constant, its kinetic energy depends only on velocity. It means if the velocity is more, it will have maximum kinetic energy. For the interval of 31-40 m/s, the kinetic energy of the object is maximum.
Answer: [B]: " (180 <span>- 4y)° " .
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Answer:
a. 5A
b. 39.60%
Explanation:
The computation is shown below:
a. The current does it draw is
= v ÷ R
= 110v ÷ 22
= 5A
b. Now the efficiency of the motor is
n = mgh ÷ vlt
= (10,000 × 9.8 × 8) ÷ (5 × 3600 × 110)
= 784000 J ÷ 1,980,000
= 39.60%
hence, the above formulas are applied & the same is relevant
Answer:
a) 19.2 s
b) No
Explanation:
Given:
v₀ = 125 m/s
a = -6.5 m/s²
v = 0 m/s
a) Find: t
v = at + v₀
(0 m/s) = (-6.5 m/s²) t + (125 m/s)
t ≈ 19.2 s
b) Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (125 m/s)² + 2 (-6.5 m/s²) Δx
Δx ≈ 1200 m
An aircraft carrier that's 850 meters long won't be long enough.
