1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mojhsa [17]
3 years ago
11

Ls are used to analyze large unstructured data sets, such as e-mail, memos, survey responses, etc., to discover patterns and rel

ationships. question 10 options:
Physics
1 answer:
Kruka [31]3 years ago
6 0
The word that could fit to this is Text Mining. This word also referred to as text data mining, roughly equivalent to text analytics, a process of deriving high-quality information from text. This high quality information derived through the devising of patterns and trends through means such as statistical patter learning. 
You might be interested in
A blow dryer transfers thermal energy mainly by
AlekseyPX

Answer:

B

Explanation:

Through air

4 0
3 years ago
Read 2 more answers
Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19
aleksandr82 [10.1K]

Answer:

The answer to your question is distance between these electrons

                                                   = 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

  F = kq₁q₂ / r²

-Solve for r²

  r² = kq₁q₂ / F

-Substitution

  r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

- Simplification

  r² = 2.306 x 10⁻²⁸ / 1.2

  r² = 1.922 x 10⁻²⁸

-Result

  r = 1.386 x 10⁻¹⁴ m

7 0
4 years ago
a 10 kg solid disk of radius 0.5 m is rotated about an axis through its center.the disk accelerates from rest to angular speed o
mezya [45]

Answer:

τ ≈ 0.90 N•m

F =

Explanation:

I = ½mR² = ½(10)0.5² = 1.25 kg•m²

α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²

τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m

τ = FR

Now we have the unanswered question of reference frame.

80° from what?

If it's 80° from the radial

F = τ/Rsinθ = 0.90/0.5sin80 = 1.818...  ≈ 1.8 N

If it's If it's 80° from the tangential

F = τ/Rcosθ = 0.90/0.5cos80 = 10.311...  ≈ 10 N

There are an infinite number of other potential solutions

7 0
3 years ago
A student must design an experiment to determine the gravitational mass of an object. Which of the following experiments could t
Elena L [17]

Answer: a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.

d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.

Explanation:

The options are:

a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.

b. Place the object on a surface of negligible friction and pull the object horizontally across the surface with a spring scale at a non constant speed such that a motion detector can measure how the objects speed as a function of time changes.

c. Place the object on a surface that provides friction between the object and the surface. Use a surface such that the coefficient of friction between the object and the surface is known. Pull the object horizontally across the surface with a spring scale at a nonconstant speed such that a motion detector can measure how the objects speed as a function of time changes.

d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.

Gravitational mass simply has to do with how the body responds to the force of gravity. From the options given, the correct options are A and D.

For option A, by balancing the torque, the mass can be calculated. Since the known mass and the distance has been given here, the unknown mass can be calculated.

For option D, here the gravitational force can be balanced by the spring force and hence the mass can be calculated.

5 0
3 years ago
Compare and contraste tanker truck carrying a liquid load and a truck carrying solid objects?
notka56 [123]
All you need to do is add them together
7 0
3 years ago
Other questions:
  • Two parallel wires are separated by 6.10 cm, each carrying 2.85 A of current in the same direction. (a) What is the magnitude of
    5·1 answer
  • Physics Question:<br> (ignore the part crossed in red) 14459688
    15·1 answer
  • How much force is needed to accelerate a 1245 kg car at a rate of 4.25<br> m/sec^2?
    11·1 answer
  • A simple pendulum consists of a small object with mass m = 1.91 kg and a massless string with length l = 1 m. Halfway down the s
    14·1 answer
  • What single property was the most important in Jesseca’s material?
    5·2 answers
  • Which of the following is the largest mass? A 5 kilograms b 1 000 milligrams C 800 centigrams D 100 grams
    14·1 answer
  • Estimate the number of photons emitted per second from 1.0 cm2 of a person's skin if a typical emitted photon has a wavelength o
    9·1 answer
  • An artificial satellite circling the Earth completes each orbit in 130 minutes. (a) Find the altitude of the satellite. Your res
    7·1 answer
  • Which of the following accurately describes the process of Gas Exchange? *
    8·1 answer
  • Alex is driving at constant velocity of 30 mph. How far does he travel in 2.5 hours?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!