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devlian [24]
3 years ago
10

The energy needed to get a reaction started is the

Physics
1 answer:
Leto [7]3 years ago
4 0
The energy needed to get a reaction started is the B. Activation Energy
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What is the relationship between matter and energy as it changes states of matter (phase changes?)
AlekseyPX

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. The example we will use here is ice melting into water.

7 0
3 years ago
A woman does 236 J of work
Ratling [72]

Answer:

The woman's force was directed 59.22⁰ to the horizontal.

Explanation:

Given;

work done by the woman, W = 236 J

distance through the load was moved, d = 24.4 m

applied force, F = 18.9 N

inclination of the force, = θ

The work done by the woman is calculated as;

W = Fdcosθ

cos \ \theta = \frac{W}{Fd} \\\\cos \ \theta = \frac{236 }{18.9 \times 24.4} \\\\cos \ \theta =  0.5118\\\\\theta = cos^{-1} ( 0.5118)\\\\\theta =59.22^0

Therefore, the woman's force was directed 59.22⁰ to the horizontal.

8 0
3 years ago
Earth rotates on is axis approximately once every 24 hours, causing the day to night cycle and?
katovenus [111]
Yes this is true this causes day and night
6 0
3 years ago
calculate the density of a neutron star with a radius 1.05 x10^4 m, assuming the mass is distributed uniformly. Treat the neutro
Orlov [11]

To develop this problem it is necessary to apply the concepts related to the proportion of a neutron star referring to the sun and density as a function of mass and volume.

Mathematically it can be expressed as

\rho = \frac{m}{V}

Where

m = Mass (Neutron at this case)

V = Volume

The mass of the neutron star is 1.4times to that of the mass of the sun

The volume of a sphere is determined by the equation

V = \frac{4}{3}\pi R^3

Replacing at the equation we have that

\rho = \frac{1.4m_{sun}}{\frac{4}{3}\pi R^3}

\rho = \frac{1.4(1.989*10^{30})}{\frac{4}{3}\pi (1.05*10^4)^3}

\rho = 5.75*10^{17}kg/m^3

Therefore the density of a neutron star is 5.75*10^{17}kg/m^3

4 0
3 years ago
A pumpkin weighs 5.4 pounds what is its mass in grams?
olga nikolaevna [1]
THe answer would be 2,449.4 grams
8 0
3 years ago
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