Expand the expression as
(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵
… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵
Then taking the inverse transform, you get
LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]
… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]
… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]
… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴
It would take 5 yrs. for both trees to be the same height.
A 10% booking fee is added to the ticket price (I'm guessing 10% is added for each ticket)
Find 10% of the adult and child ticket:
10% of 15 = 1.5
10% of 10 = 1
find the total price for the 4 adult tickets he buys and 2 child tickets:
(15 +1.5) × 4 = 66
(10 + 1) × 2 = 22
66 + 22 = 88
1.5% will then be added if he lays by credit card :
1.5% of 88 = 1.32
total :
88 + 1.32 = 89.32
He pays a total of £89.32
Answer:
580
Step-by-step explanation: