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Sedaia [141]
2 years ago
10

The logarithmic expression

a1" title="log_{b}(\frac{1}{b^{-b}} )" alt="log_{b}(\frac{1}{b^{-b}} )" align="absmiddle" class="latex-formula"> where b > 0, is equal to
a) b^{-b}

b) b^{b}

c) -b

d) b
Mathematics
1 answer:
ivanzaharov [21]2 years ago
3 0

\log_b \left(\dfrac 1{b^{-b}}\right)\\\\=\log_b (b^{-b})^{-1}\\\\=\log_b  b^b\\\\=b \log_b b\\\\=b \cdot 1\\\\=b

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Answer:

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