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olga_2 [115]
3 years ago
13

The area of the figure is about blank

Mathematics
2 answers:
mars1129 [50]3 years ago
4 0

Answer:

61.4

Step-by-step explanation:

alina1380 [7]3 years ago
3 0

Answer:

6/2=3

3*10=30

10*3.14=31.4

30+31.4=61.4 or rounded to 61

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Sergeeva-Olga [200]

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<h3>stay safe healthy and happy.</h3>
8 0
3 years ago
Read 2 more answers
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Simplify.<br><br>(7y)^2<br><br>Write your answer without parentheses.
kiruha [24]

Answer:

Step-by-step explanation:

(7y)² = 7²×y² = 49y²

4 0
3 years ago
Patrick picked two numbers. The first number has 7 hundreds, 0 tens, and 0 ones. The second number has 2 fewer hundreds than the
pshichka [43]

Answer:

500 and 700

Step-by-step explanation:

It says '7 hundreds' referring to 700. and it then say the second number has 2 fewer, two fewer hundreds is 200. so the two numbers are 500 and 700.

8 0
2 years ago
The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x. step by step explanation.​
mars1129 [50]

Answer:

The area of the rectangle in terms of 'x' = 13x

Step-by-step explanation:

  • Perimeter = 30 cm
  • Length = x cm

Using the perimeter formula to find the width w.

P=2(l+w)

P = 2l + 2w

2w = P-2l

Dividing both sides by 2

w\:=\:\frac{P}{2}-2

as P = 30 cm

w\:=\:\frac{30}{2}-2

w\:=\:15-2

w = 13 cm

Using the formula of the rectangle area

A = wl

substitute w = 13 and l = x in the formula

A=13\times \:x

A = 13x

Therefore, the area of the rectangle in terms of 'x' = 13x

7 0
2 years ago
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