You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²) b = 9.16
With these values, we can find the hypotenuse in the triangle "B": x = √b²+c² x = √(9.16)²+(4)² x = 10
Judging by the question at hand I generated this equation.
x+y=12
x=2y
I begin this question by plugging in the x=2y into the equation for x.
So the new equation should be 3y=12. I then divide the entire equation by 3 to get y=4.
Next I plug y=4 into the equation, the new equation should be x+4=12. I then subtract 4 from both sides to get x=8.
The two numbers are :
x=8 y=4
Answer:
-6 ≤x
Step-by-step explanation:
3x-2≤5(x+2)
Distribute
3x-2≤5x+10
Subtract 3x
3x-2-3x≤5x +10-3x
-2 ≤2x+10
Subtract 10 from each side
-2-10 ≤2x+10-10
-12 ≤2x
Divide by 2
-12/2≤2x/2
-6 ≤x
Answer:
the anwser is b
Step-by-step explanation:
divide 27 by 180 and you get an answer of 54
