Answer:
18mL of the 20% solution must be mixed with 10 mL of the 6% solution to
obtain the desired 15% solution
Step-by-step explanation:
Ignore all of the useless information til the last sentence: How many milliliters of the 20% solution must be mixed with 10 mL of the 6% solution to obtain the desired 15% solution?
Our goal is to find out how many mL of 20% solution is needed to mix with 10mL of 6% solution to achive a 15% solution.
An easy and simple way to do it is to create a system of equation:
We add in x mL of 15% solution(Which has x mL of water and 20%*x mL of salt)
The equation: 15%=(20%x+0.6)/(x+10)
After solving it we get x=18
Therefore:
18mL of the 20% solution must be mixed with 10 mL of the 6% solution to
obtain the desired 15% solution
Hope this helps, have a good day!
Ps. If you have any questions, feel free to ask them in the comment section below-I'll be more than happy to answer.
