Answer:
Angle 2=160
Angle 3=10
Step-by-step explanation:
The rhombus is made up of two isoceles triangle.
Angle 1 measures 160.
Since the triangle is a isoceles triangle, the opposite angles of the congruent sides is equal angles to each other.
So the reamaing angles in the top triangle are equal so we can use this equation
Remeber that triangle maximum degree it can hold is 180
We have two congruent triangle side they share Three sides. SSS
This means the corresponding angle of Angle 1 is Angle 2.
Angle 2=Angle 1 by CPCTC.
Angle 2=160
Angle 3 corresponds with one of the remaining congruent angles so it measures
10.
There's no such thing as the "length"of an angle.
But we know what you're getting at.
You have said that the angles are complementary. If two angles are
complementary, then their sum is 90 degrees, so we can take your
two angles and write:
<u>x</u> (one angle) plus <u>(2x + 12)</u> (the other one) <u>= 90 degrees
</u><u /> x + 2x + 12 = 90<u>
</u>Subtract 12 from each side: x + 2x = 78
Add the x's on the left side: 3x = 78
Divide each side by 3 : x = 26 degrees
One angle is 'x' = <em>26 degrees</em>
The other one is (2x + 12) = 52+12 = <em>64 degrees</em>
Answer:
wiring probably.
Step-by-step explanation:
X^2 - 6x + 9 = -1 + 9. We need to solve for x.
First, add one on each side of the equation:
x^2 - 6x + 9 + 1 = -1 + 9 + 1
x^2 - 6x + 10 = 9
Then subtract 9 from each side:
x^2 - 6x + 10 - 9 = 9-9
x^2 - 6x + 1 = 0
Now we got an equation = 0. This an equation from the second degree, it represented by a parabola which turns up since a>0.
This equation is the developed form as ax^2 + bx + c with a=1; b = -6; and c=1.
Now, to find the zeroes of this equation, we need to find delta Δ.
Δ = b^2 - 4ac.
If Δ>0, the equation admits 2 zeroes: x=(-b-√Δ)/2a and x = (-b+√Δ)/2a.
If Δ<0, the equation doesn't admits any zero.
If Δ=0, the equation admits one zero x = -b/2a
Δ = (-6)^2 - 4(1)(1)
Δ = 36 - 4
Δ = 32
Δ>0
So the zeroes of the equation are:
x = (-b-√Δ)/2a = (6-4√2)/2
x = (-b+√Δ)/2a = (6+4√2)/2
Hope this Helps! :)
90 % sure
The image attached shows an operation that can be represented with whole numbers, becuase there are positive and negative characters.
So, we know by given that there are +4 circles and -7 circles, and the whole can be expressed as the algebraic sum of them,
Therefore, the model can be represented by the number -3, which is the whole because is the result of the operation that represent each type of element.
hope i helped
-lvr
