All categories

2 years ago

Which three steps are correct when solving this quadratic equation by completing the square?

Mathematics

1 answer:

guajiro [1.7K]2 years ago

5 0

Answer:

<em><u>E</u></em>

Step-by-step explanation:

transferring the constant

making the coefficient of x^2 to be 1

then add the square of half the coefficient of x

take the square root of both sides

You might be interested in

Any one that knows this please help thanks!

OLga [1]

Replace each occurrence of x by 7. So we have:-

7^2 + 3 / 7 - 9

= 52 / -2

= -26 answer

5 0

2 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

2 years ago

Read 2 more answers

Hellllllppppppppppppppppppppppppppppp

larisa [96]

Answer:

Step-by-step explanation:

7 0

2 years ago

Find all numbers whose absolute value is 8.

Zepler [3.9K]

Answer:

Step-by-step explanation:

The absolute value of number a:

|a| = a for a ≥ 0

|a| = -a for a < 0

|a| = 8 ⇔ a = 8 or a = -8

7 0

2 years ago

What is 7÷23 including the remainder

Harlamova29_29 [7]

I hope this is helpful!

Answer: 3 R2

8 0

2 years ago

Read 2 more answers