All categories

3 years ago

Zia has a slab of concrete in the shape of a parallelogram.

Mathematics

2 answers:

Aleksandr [31]3 years ago

7 0

Answer:

270 in²

Step-by-step explanation:

The area of a parallelogram is given by the formula A = bh.

The base of the parallelogram is 9+9 = 18 inches.

The height of the parallelogram is 15 inches.

This makes the area 15(18) = 270 in²

svetlana [45]3 years ago

3 0

Answer:

Option D is correct

The area of the parallelogram is, 270 square inches.

Step-by-step explanation:

Area of parallelogram(A) is given by:

$A = bh$ ......[1]

where,

b is the base and h is the height of the parallelogram respectively.

As per the statement:

Zia has a slab of concrete in the shape of a parallelogram.

From the given diagram:

Base of the parallelogram(b) = 9+9 = 18 inches

height of the parallelogram(h) = 15 inches

Substitute the given values in [1] we have;

$A = 18 \cdot 15 = 270 in^2$

therefore, the area of the parallelogram is, 270 square inches.

You might be interested in

The sales tax for a certain state can be found by multiplying the purchase price by 1/20 . What is the sales tax on an item that

Nuetrik [128]

The answer is $1.28 sale tax
Step-by-step explanation:
Multiply the cost of the item times 0.05 to get the amount of the sales tax:
25.60 * 0.05 = $1.28 sales tax

5 0

2 years ago

Read 2 more answers

In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

5 0

2 years ago

3/4-5/4m=113/24<br> please show work

bija089 [108]

May need to change into a mixed fraction

6 0

2 years ago

Tim has 80 coins in his piggy bank. Of these coins, 28 are nickels and the rest are quarters. What percent of the coins in the b

KIM [24]

65 percent I check it

8 0

2 years ago

Read 2 more answers

Mina tosses two number cubes labeled 1 to 6. What is the probability that the sum is equal to five?

coldgirl [10]

(1,4)

(4,1)

(2,3)

(3,2)

so there are 4 different combinations that equal 5

6 x 6 = 36 total possible outcomes of the dice

so they have a 4/36 reduces to 1/9 probability of equaling 5

7 0

3 years ago