Question

I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain your answer. The chart for number 3 is attached above
In this experiment, you will be using two coins as a simulation for a real-world compound event.


1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.


What is the theoretical probability that the family has two dogs or two cats?

2. Describe how to use two coins to simulate which two pets the family has.

3. Flip both coins 50 times and record your data in a table like the one below. ( the chart is the picture that I attached)


Result Frequency

Heads, Heads

Heads, Tails

Tails, Heads

Tails, Tails

Total 50

Based on your data, what is the experimental probability that the family has two dogs or two cats?

4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

5. How could you change the simulation to generate data for three pets?

Answer 1

1.) Equal likely chance would be 50/50 for having a dog or a cat. There are 3 possibilities: one dog and one cat, 50%, two dogs, 25%, or two cats, 25%. Adding the probabilities of having two of the same pets would theoretically give you a 50% chance.

2.) If you used two coins to simulate the possible outcome of pets the family had, you would have two fair sided coins. Each coin would have one dog side and one cat side (or heads and tails, where you would assign each pet a side of the coin).

3.) You have to do the expirament on your own.

4.) Having three pets changes the probability to a 33.3% chance of having each pet. Using number one as an example, add the probabilities to get a 66.6% chance for having three of the same pets.

5.) You can change the simulation by using a 3-sided die.

Answer 2

Answer:

awnsered because you can give other guy brainlist

Step-by-step explanation: