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luda_lava [24]
4 years ago
7

Daniel took two quizzes. On the first he earned 9.5 points per question plus 2 bonus points. On the second he earned 11.5 points

per question plus 1 bonus point. The expression for the average number of points Daniel earned is , where q represents the number of questions per quiz.
What is Daniel’s average number of points if q = 8?
Mathematics
1 answer:
Gekata [30.6K]4 years ago
7 0
On quiz 1 he would have made a 78 because 9.5*8=76+2=78

On quiz 2 he would have made a 93 because 11.5*8=92+1=93

Hope this helps! 
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Four friends were born on consecutive years. The sum of their ages is 62. What is the age of the youngest friend?
Yuri [45]
<span>Four friends were born on consecutive years.
The sum of their ages is 62. Let's find the age of the youngest friend:
</span><span>Formula:
4x + 6 = 62
=> First is to Subtract 6 from both sides 4x = 56
Then next thing to do is to divide 4 from both sides:
=> x = 14 14 + 14 + 1 + 14 + 2 + 14 + 3 = 62
 62 = 62
 Thus the youngest age is 14</span>
7 0
3 years ago
Which fraction is NOT equivalent to
Alenkinab [10]

1/3

7/12

9/12

1/4

and more

3 0
3 years ago
Help! Please! <br> Find the length of the midsegment.<br> 44<br> 22<br> 13<br> 15
sergiy2304 [10]
(5x + 2)/(3x + 32) = 24/48
(5x + 2)/(3x + 32) = 1/2
2(5x + 2) = 3x + 32
10x + 4 = 3x + 32
7x = 28
  x = 4

Mid segment = 5(4) + 2 = 20 + 2 = 22

Answer
22
4 0
3 years ago
Read 2 more answers
Find the equation of the parallel to the line 3x-2y=5 and passing through the midpoint of the line segment joining the points (-
levacccp [35]

Given:

The equation of parallel line is:

3x-2y=5

The required line passing through the midpoint of the line segment joining the points (-4,2) and (2,4).​

To find:

The equation of required line.

Solution:

Midpoint of  line segment joining the points (-4,2) and (2,4) is:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+2}{2},\dfrac{2+4}{2}\right)

Midpoint=\left(\dfrac{-2}{2},\dfrac{6}{2}\right)

Midpoint=\left(-1,3\right)

It means the required line passes through the point (-1,3).

The slope of line Ax+By=C is:

m=\dfrac{-A}{B}

The given equation is:

3x-2y=5

Here, A=3 and B=-2. So, the slope of the line is:

m=\dfrac{-3}{-2}

m=1.5

Slope of parallel lines are same. So, the slope of the required line is 1.5.

The required line passes through the point (-1,3) with slope 1.5. So, the equation of the line is:

y-y_1=m(x-x_1)

y-3=1.5(x-(-1))

y-3=1.5(x+1)

y-3=1.5x+1.5

Adding 3 on both sides, we get

y=1.5x+1.5+3

y=1.5x+4.5

Therefore, the equation of the required line is y=1.5x+4.5.

8 0
3 years ago
Nicole simplifies 2^a*2^5/2^b to 2^(a-b+5). Which two properties of exponents did she use while simplifying the expression?
emmainna [20.7K]

Answer:

D.

Step-by-step explanation:

2^a*2^5/2^b = 2^(a+5)/2^b. using power of a product property.

then

2^(a+5)/2^b= 2^(a+5)*2^-b. Using Negative Exponent property.

Again we can use power of a product property and we get 2^(a+5)*2^-b=2^(a-b+5)

5 0
3 years ago
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