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3 years ago

Explain why is 1/5 bigger than 0.15

1 answer:

8 0

1/5 is greater because it equals 0.2

0.2 has an imaginary 0 at the end, to make it 0.20

.20 > 0.15

Therefore, 1/5 is greater than 0.15

You might be interested in

How are the coordinates of the extreme value and the equation from part B in the form y=(x-h)^2-c related.

True [87]

The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

if a > 0 (h', k) is a minimum point and
if a < 0 (h', k) is a maximum point.

Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

h = h'
-c = k and
a = 1.

So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

Learn more about extreme value of a function here:

brainly.com/question/13464558

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4 0

1 year ago

Which is the polynomial function of lowest degree with rational real coefficients, a leading coefficient of 3 and roots StartRoo

anastassius [24]

Answer:

$a) f(x)=3x^{3}-6x^{2}-15x+30$

Step-by-step explanation:

1) In this question we've been given "a", the leading coefficient. and two roots:

$x_{1}=\sqrt{5}\:x_{2}=2$

2) There's a theorem, called the Irrational Theorem Root that states:

If one root is in this form $x'=\sqrt{a}+b$ then its conjugate $x''=\sqrt{a}-b$ . is also a root of this polynomial.

Therefore

$x_3=-\sqrt{5}$

3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:

$f(x)=3(x-\sqrt{5})(x+\sqrt{5})(x-2)\Rightarrow 3x^{3}-6x^{2}-15x+30$

4 0

2 years ago

Read 2 more answers

Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between

ivolga24 [154]

Answer:

197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

AB = 50*2 = 100 km
AC = 70*2 = 140 km

The angle between AB and AC is:

60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

BC² = AB² + AC² - 2AB*AC*cos ∠BAC

BC² = 100² + 140² - 2*100*140*cos 110°
BC² = 39176.56 (rounded)
BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

7 0

1 year ago

Equations in the Form y = ax^2

ra1l [238]

Answer:

Step-by-step explanation:

It's 2 because 4^2 is 8 and 1^2 is 2 so that's how I got my answer

8 0

2 years ago

Root of 3 time the root of <br> 5

zimovet [89]

Answer:

root of 15 or in decimal form 3.87 (rounded)

Step-by-step explanation:

You just multiply both together

3 0

2 years ago