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fredd [130]
2 years ago
15

Please solve I need to pass this text

Mathematics
2 answers:
VARVARA [1.3K]2 years ago
6 0

Answer:

4/15 deeper than the 1st dive

Step-by-step explanation:

make the 1st and 2nd dive have the same denotator. so

1st dive:5/15

2nd dive:9/15

subtract the 1st dive with the 2nd.

9/15-5/15=4/15

Sindrei [870]2 years ago
3 0

Answer:

4/15

Step-by-step explanation:

1/3 = 5/15

3/5 = 9/15

9-5 = 4

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Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size  'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample  S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size  n₂ = 24</em>

<em>mean of the second sample  "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample  S₂ =  2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em>    </em>t = \frac{x^{-} _{1} -  x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} }  }

<em>    where         </em>S^{2}   = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2}   }{n_{1} +n_{2} -2}

                      S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}

<em>              substitute values and we get  S² =  40.988</em>

<em>     </em>t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24}  )}<em></em>

<em>  </em>   t =  1.3622

  Calculated value t = 1.3622

Tabulated value 't' =  2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em>      </em>

<em>                        </em>

<em>                    </em>

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