Answer:
x = 3
Step-by-step explanation:
7/x - 3/(2x) + 7/6 = 9/x
x(7/x - 3/(2x) + 7/6) = x(9x)
x*7/x - 3*x/(2x) + x*7/6 = x*9x
7 - 3/2 + 7x/6 = 9
7x/6 = 9 - 7 + 3/2
7x/6 = 2 + 3/2
7x/6 = 12/6 + 9/6
7x = 12+9
7x = 21
x = 21/7
x = 3
probe:
7/3 - 3/(2*3) + 7/6 = 9/3
14/6 - 3/6 + 7/6 = 3
(14 - 3 + 7) / 6 = 3
18/6 = 3
The answer is 6. 480 divided by 80 gives you the answer 6.
Answer:
Step-by-step explanation:
First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.
If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.
After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form
y = ±
Filling in our asymptotes as they were given to us:
y = ±
where a is 2 and b is 1. Now we can write the formula for the hyperbola!:
which of course simplifies to

1. Each number on the second line of the table is 5 times that on the first line. Costs are: $1000, $2000, $2500
2. c = 5t . . . t > 0
3. Each number on the second line of the table is 15 times the magnitude of that on the first line. Costs are: $3000, $6000, $7500
4. c = -15t . . . t < 0 . . . . . . . . . . could also be written as c = 15·|x|
5. One constant of proportionality is negative because the domain it operates on is negative and the desired result is positive.
QPN and TSU !!!! they are both angles on the exterior with a larger value!!