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3 years ago

Write an equation of the line that passes through point (-1, 5) and has the slope m = 4.

Mathematics

1 answer:

hram777 [196]3 years ago

5 0

You want to find the equation for a line that passes through the point (-1,5) and has a slope of 4.
First of all, remember what the equation of a line is:

y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 4. So you can right away fill in the equation for a line somewhat to read:
y=4x+b.
Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:
(-1,5). When x of the line is -1, y of the line must be 5.

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A vegetable garden and a surrounding as a shaped like a square that together a 11 ft wide. The path is 2 feet wide. If one bag o

Alexxandr [17]

Answer:

$\displaystyle 4$

Step-by-step explanation:

we are given that A vegetable garden and a surrounding as a shaped like a square that together a 11 ft wide. The path is 2 feet wide.since together the width of Vegetable garden and path is 11 ft, the width of the vegetables garden will be the difference between the total width and the width of path Thus,

$\displaystyle \rm W _{ garden} = 11 - 2$

simplify substraction:

$\displaystyle \rm W _{ garden} = 9$

recall that, every single side of a square is equal to each other therefore the the area of the garden will be

$\displaystyle {9}^{2}$

simplify square:

$\displaystyle 81$

together the garden and path makes a square of every side length 11 ft saying that the area will be:

$\displaystyle {11}^{2}$

simplify square:

$\displaystyle 121$

the area of path will be the difference between the total area and the garden area therefore,

$\displaystyle 121 - 81$

simplify addition:

$\displaystyle 40$

to figure out how many bags are needed to cover the path. we just need to divide the area of the path by the area of a bag of gravel and that yields:

$\displaystyle \frac{40}{10}$

simplify division:

$\displaystyle \boxed{\rm4}$

hence,

4 bags are needed to cover the path.

7 0

3 years ago

A sheet of paper has a perimeter of 39 in. if the width of the paper is 8.5 in . what is the length of the sheet of paper

Valentin [98]

If the perimeter is 39 what you have to do is 39 - 8.5 - 8.5 that will give you 22 and divide 22/2 and that gives you 11. So 11 is the length

5 0

3 years ago

Read 2 more answers

What is slope intercept for 7x+6y=30

GalinKa [24]

7x+6y=30
6y = -7x + 30
y = -7/6x + 5

answer:
slope = -7/6

4 0

3 years ago

Read 2 more answers

If 57 is added to a number, it will be 4 times as large as it was originally. Find the number.

Sonja [21]

Answer:

Step-by-step explanation:

X will refer to the number.

X+57( the number added to the original.)=4x. (x time 4)

X+57=4x.

Subtract x from both sides to get the variable on one side.

(X+57)-x =(4x)-x

57=3x. You would then divide by 3 on both sides to again get integer isolated.

57/3=3/3x.

57/3=19. 3/3=1.

19=x.

6 0

3 years ago

En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Nonamiya [84]

Answer:

$\displaystyle \tan A=\frac{4}{3}$

Step-by-step explanation:

Funciones Trigonométricas

La identidad principal en trigonometría es:

$sen^2A+cos^2A=1$

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

$cos^2A=1-sen^2A$

Sustituyendo:

$\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2$

$\displaystyle cos^2A=1-\frac{16}{25}$

$\displaystyle cos^2A=\frac{25-16}{25}$

$\displaystyle cos^2A=\frac{9}{25}$

Tomando raíz cuadrada:

$\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}$

La tangente se define como:

$\displaystyle \tan A=\frac{sen\ A}{cos\ A}$

Substituyendo:

$\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}$

$\displaystyle \tan A=\frac{4}{3}$

6 0

3 years ago