Step-by-step explanation:
Area of Rectangle at the top =
Length x Width
Area of Quarter- Circle = 1/4 x Area of Circle
Area of Rectangle at the right = Length x Width
Total Area = Area of 2 Rectangles + Area of Quarter Circle
I will leave the answer in terms of pi as I'm not sure if you need to round off your answer.
Answer:
x = 12
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the external part and the entire secant, that is
x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )
x = = 12
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)