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3 years ago

Help me please just help I need help rn like rn

Mathematics

1 answer:

alexgriva [62]3 years ago

6 0

Answer:

i.900

j.6

k.8

l.0

Step-by-step explanation:

hope this helps you ;)

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the probability of winning a game is 20%. if you play 20 times how many times should you expect to win

julia-pushkina [17]

The probability of winning a game out of 20 is 4 times.

6 0

3 years ago

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The purchasing power P of a fixed income of $20000 per year (such as a pension) after t years of 7% inflation can be modeled by

Oxana [17]

After 5 years: 107,000

After 20 years: 428,000

7 0

3 years ago

Darcy harvests 8 3/4 acres of corn every 5/6 of an hour. Darcy harvests corn at a constant rate. How many acres does she harvest

Inessa05 [86]

Answer: 10 1/2, which can be simplified as 10.5

Explanation: First, set up a proportion with acres of corn to time in hours:

8 3/4 acres = x acres

5/6 hour = 1 hour

Reorder the terms:

x = (8 3/4) / (5/6)

To figure that out the math, change the mixed fraction to an improper fraction, and change the division into a multiplication:

x = (35/4) * (6/5)

Next cancel out:

x = (7/2) * (3/1)

x = 21/2

Lower that faction the the lowest denominator:

21/2 = 10½

Thus, your answer is 10½, or in other words 10.5

Hope this helps! :)

5 0

3 years ago

A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the

denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

$y=\frac{20}{x^{3} }$ -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

= $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost $C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}$

$C=0.35x^{2}+\frac{8}{x}+0.15x^{2}$

$C=0.5x^{2}+\frac{8}{x}$

Now we take the derivative of C with respect to x and equate it to zero,

$C'=0.5(2x)-\frac{8}{x^{2}}$ = 0

$x-\frac{8}{x^{2}}=0$

$x=\frac{8}{x^{2} }$

$x^{3}=8$

x = 2 ft.

From equation (1),

$(2)^{2}y=20$

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0

3 years ago

A buliding 78ft high casts a 195ft shadow on sarah. sarah casts a 10ft shadow. how tall is sarah?

sergejj [24]

Answer:

4 ft

Step-by-step explanation:

195/78=2.5

10/2.5=4

5 0

3 years ago