The probability the 51st call arriaves within 150hours is 0.0431, the probability the next call arrives within the next 2 hours 0.5488, the probability the sum of these 50 numbers is less than 356 is 0.4165.
Data;
- Mean rate = 0.3
- x = 50
- standard deviation = ?
<h3>Poission Rule</h3>
Using poission formula,
![P(x=x) = \frac{e^-^\lambda - \lambda^x}{x!}\\\lambda = 0.3 per minute](https://tex.z-dn.net/?f=P%28x%3Dx%29%20%3D%20%5Cfrac%7Be%5E-%5E%5Clambda%20-%20%5Clambda%5Ex%7D%7Bx%21%7D%5C%5C%5Clambda%20%3D%200.3%20per%20minute)
Let's substitute the values into the formula.
For 50 calls in 150 hours
For 150 hours = x = 0.3 * 150 = 45
![p(x=50) = \frac{e^-^4^5 * 45^5^0}{50!} = 0.0431](https://tex.z-dn.net/?f=p%28x%3D50%29%20%3D%20%5Cfrac%7Be%5E-%5E4%5E5%20%2A%2045%5E5%5E0%7D%7B50%21%7D%20%3D%200.0431)
b)
The probability the next call arrives after 2 hours.
![\lambda = 0.3 * 2 = 0.6\\p(x=0) = \frac{e^-^0^.^6 * 0.6^0}{0!} = 0.5488](https://tex.z-dn.net/?f=%5Clambda%20%3D%200.3%20%2A%202%20%3D%200.6%5C%5Cp%28x%3D0%29%20%3D%20%5Cfrac%7Be%5E-%5E0%5E.%5E6%20%2A%200.6%5E0%7D%7B0%21%7D%20%3D%200.5488)
c)
The number of calls recieved each day is recorded for 50 consecutive days.
for 50 days;
![\lambda = 0.3 * 50 * 24 = 360](https://tex.z-dn.net/?f=%5Clambda%20%3D%200.3%20%2A%2050%20%2A%2024%20%3D%20360)
The mean = 360
The standard deviation is given as
![S.D = \sigma =\sqrt{360} = 18.974\\](https://tex.z-dn.net/?f=S.D%20%3D%20%5Csigma%20%3D%5Csqrt%7B360%7D%20%3D%2018.974%5C%5C)
The probability the sum of these 50 number is less than 356 is
![p = (x < 356) = z = \frac{356 - 360}{18.974} = -0.2108\\p(z < -0.2108) = 0.4165](https://tex.z-dn.net/?f=p%20%3D%20%28x%20%3C%20356%29%20%3D%20z%20%3D%20%5Cfrac%7B356%20-%20360%7D%7B18.974%7D%20%3D%20-0.2108%5C%5Cp%28z%20%3C%20-0.2108%29%20%3D%200.4165)
Learn more on poission formula here;
brainly.com/question/7879375
Answer:
Subtract 23 from both sides
Step-by-step explanation:
This is how algebra works, to get a variable by itself you have to do the opposite to both sides. Hope this helped.
Answer:
The better value is 5pounds for $11
Step-by-step explanation:
2.75×5= $13.75
so the 5 pounds for $11 would be better because the other option would cost $13.75 for the same amount
Answer:
47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth
Step-by-step explanation:
For each individual, there are only two possible outcomes. Either they cover their mouth when sneezing, or they do not. The probability of an individual covering their mouth when sneezing is independent of other individuals. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
According to a study done by Otago University, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267.
This means that ![p = 0.267](https://tex.z-dn.net/?f=p%20%3D%200.267)
What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth
10 individuals, so n = 10.
![P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29)
In which
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{10,0}.(0.267)^{0}.(0.733)^{10} = 0.0448](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B10%2C0%7D.%280.267%29%5E%7B0%7D.%280.733%29%5E%7B10%7D%20%3D%200.0448)
![P(X = 1) = C_{10,1}.(0.267)^{1}.(0.733)^{9} = 0.1631](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B10%2C1%7D.%280.267%29%5E%7B1%7D.%280.733%29%5E%7B9%7D%20%3D%200.1631)
![P(X = 2) = C_{10,2}.(0.267)^{2}.(0.733)^{8} = 0.2673](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20C_%7B10%2C2%7D.%280.267%29%5E%7B2%7D.%280.733%29%5E%7B8%7D%20%3D%200.2673)
![P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0448 + 0.1631 + 0.2673 = 0.4752](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29%20%3D%200.0448%20%2B%200.1631%20%2B%200.2673%20%3D%200.4752)
47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth
The care has gone 60m in 12 seconds