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Serjik [45]
2 years ago
14

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem

ium antifreeze solution contains 95% pure antifreeze. The company wants to obtain 285 gallons of a mixture that contains 55% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?
Mathematics
1 answer:
Ne4ueva [31]2 years ago
6 0

Answer:

  • premium: 165 gallons
  • water: 120 gallons

Step-by-step explanation:

Let 'a' represent the amount of 95% antifreeze in the mix. Then the amount of water is (285 -a). The mix has this amount of antifreeze in it:

  0.95a +0(285 -a) = 0.55(285)

  a = 0.55/0.95(285) = 165 . . . gallons of 95%

  285 -a = 285 -165 = 120 . . . . gallons of water

There are 120 gallons of water and 165 gallons of premium antifreeze in the mixture.

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2 years ago
Henry is an avid reader.He devours 90 pages in half-an-hour.How many pages has Henry read per minute?
ICE Princess25 [194]

Answer:

3 pages per minute

Step-by-step explanation:

Half an hour is eqquivalent to 30 minutes, so we do 90 (pages) / 30 (minutes) = 3--> Wich means that Henry can read 3 pages per minute.

4 0
3 years ago
Read 2 more answers
Graph the first six terms of a sequence where a1 = −10 and d = 3.
Neko [114]

notice the first term is -10, and the common difference is 3, so we add 3 to get the next term.

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8 0
3 years ago
Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor
Dahasolnce [82]

Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

<u>Solution:</u>

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is \frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }

If they work together they can do the entire prospectus in five hours

\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}

On cross-multiplication we get,

\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}

\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}

On cross multiplication ,we get

\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}

<em><u>using quadratic formula:-</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

x=\frac{12 \pm \sqrt{144-40}}{2}

\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

3 0
3 years ago
What are RQS and TQS?
yaroslaw [1]

Answer:

m∠RQS = 72°

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Step-by-step explanation:

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So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

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Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

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But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

8 0
3 years ago
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