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MakcuM [25]
2 years ago
11

Luis was hired to make some jewelry for a special occasion. He needs to make the jewelry out of an alloy that is 54%silver and h

e requires 10 ounces. He has a large amount of 45% silver and also some that is 75% silver. How many ounces of 45% silver and 75% silver does he need?
Mathematics
1 answer:
AleksAgata [21]2 years ago
8 0

9514 1404 393

Answer:

  • 3 ounces of 75%
  • 7 ounces of 45%

Step-by-step explanation:

Let x represent the number of ounces of 75% silver needed. Then (10-x) is the number of ounces of 45% silver. The total silver required is ...

  0.75x +0.45(10 -x) = 0.54(10)

  0.30x +4.5 = 5.4

  0.30x = 0.9

  x = 0.9/0.3 = 3 . . . . . ounces of 75% silver

  10-x = 7 . . . . . ounces of 45% silver

Luis needs 7 ounces of 45% silver and 3 ounces of 75% silver.

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Okay, for this one I would use elimination:

8x+(-2y)-10
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8x-2y=10
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8(2y)-2y=10
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x=10/7 or 1 3/7. Hope it help!
8 0
3 years ago
A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
2 years ago
A spider has 8 legs. An ant has 6 legs. There are a group of spiders and a group of ants. The groups have equal numbers of legs.
Lemur [1.5K]
There are three spiders and 4 ants in all
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2 years ago
The sides of a rectangle are scaled to be 1/4 of their original size
Advocard [28]
The answer is in fact D
5 0
2 years ago
Please HELP!! I’ll mark you as brainliest
disa [49]
The correct choice is C .
5 0
2 years ago
Read 2 more answers
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