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blagie [28]
3 years ago
7

4.8m into centimeters

Mathematics
2 answers:
azamat3 years ago
8 0

Answer:

4.8 metres = 480 centimetres

Step-by-step explanation:

1 m is 100 cm

so 4.8 m is 4.8 * 100 = 480 cm

Daniel [21]3 years ago
7 0

1 meter is 100 centimeters

4 meters is 400 meters

4.8 meters is 480.

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Please helppppp
earnstyle [38]

Answer:

I think B

Cuz : he said that the medicine is equal to two-thirds the weight of the child's in pound which means 2/3 multiple 45 is 30

Isn't it?

4 0
3 years ago
Is the relationship linear, exponential, or neither?
kati45 [8]

Answer:

Neither linear nor exponential

Step-by-step explanation:

To check for a linear relationship.  Find slope.

slope=  (-1  -  (-2)) / ( 5 - 2)  = 1/3

check  other points

slope = (1 - (-1) )/ (8 - 5) =  2/3

check more

slope = (4 - 1) / (11 - 8) = 3/ 3 = 1

Nope.

try assuming an exponential:

y = c * (a^x)

-2 =  c* (a^2);    -2/c = a^2

-1 = c *(a ^5);    -1/c = a^5

1 =  c * (a^8),     1/c = a^8

(-2/c)^4 = a^8 = 1/c

16/(c^4) = 1/c

c^3 = 16,  then    a = root (-2/ cube-root(16) )

The change from negative to postive  would not work  for y = c(a^x)

so...

assume   y =  a^x  + k

-2 = a^2  + k

-1 = a^5  + k

...  I would say neither..

6 0
3 years ago
The value of a machine depreciates each year by 5% of its value at the beginning of that year.If its value when new on 1st Janua
luda_lava [24]

Answer:

6460 pounds approx.

Step-by-step explanation:

Depreciation = P( 1 - r/100)^n [ n = time period, P= Principal and r= rate}

= 10,250(1-5/100)^9

= Approx. 6460 pounds

7 0
3 years ago
16 2/3 percent of what number is 72
MArishka [77]
The answer is about 432.178
6 0
4 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Ksju [112]

Answer:converge at I=\frac{1}{3}

Step-by-step explanation:

Given

Improper Integral I is given as

I=\int^{\infty}_{3}\frac{1}{x^2}dx

integration of \frac{1}{x^2}  is  -\frac{1}{x}

I=\left [ -\frac{1}{x}\right ]^{\infty}_3

substituting value

I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]

I=-\left [ 0-\frac{1}{3}\right ]

I=\frac{1}{3}

so the value of integral converges at \frac{1}{3}

8 0
4 years ago
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