The answer is b -9 < x < 12
Step-by-step explanation:

In this case we have:
Δx = 3/n
b − a = 3
a = 1
b = 4
So the integral is:
∫₁⁴ √x dx
To evaluate the integral, we write the radical as an exponent.
∫₁⁴ x^½ dx
= ⅔ x^³/₂ + C |₁⁴
= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)
= ⅔ (8) + C − ⅔ − C
= 14/3
If ∫₁⁴ f(x) dx = e⁴ − e, then:
∫₁⁴ (2f(x) − 1) dx
= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx
= 2 (e⁴ − e) − (x + C) |₁⁴
= 2e⁴ − 2e − 3
∫ sec²(x/k) dx
k ∫ 1/k sec²(x/k) dx
k tan(x/k) + C
Evaluating between x=0 and x=π/2:
k tan(π/(2k)) + C − (k tan(0) + C)
k tan(π/(2k))
Setting this equal to k:
k tan(π/(2k)) = k
tan(π/(2k)) = 1
π/(2k) = π/4
1/(2k) = 1/4
2k = 4
k = 2
To find if one is a function, you must see if the pattern is the same.
Domains (x) can not have two values
I forget what the y value is called, but there can be the same y- value for multiple x - values
A. is not a function, because its ordered pairs are all over the place, and the value 4 in the x - value has two values assigned - 0 and 3, which makes it invalid.
B. may be a linear function. Its ordered pairs aren't jumping all over the place.
Both the x and y go up one for one, so the function could be y = x + 3
C. isn't because the x - value 2 has two values. Again, that makes this invalid.
D. is invalid because there is two x - values for 2.
Therefore, the answer is B.
Answer:
-3.5
The distance Rachel covers per hour is 3.5 miles
Step-by-step explanation:
After 2 hours, she is 13 miles from the campground.
After 4 hours, she is 6 miles from the campground.
Let x be the number of hours, y be the number of miles from the campground, then we have two points (2,13) and (4,6).
The equation of the line passing through the points
and
is

Substitute:

Hence,

The slope of the line is
and it represents that the distance Rachel covers per hour is 3.5 miles.
Answer:
<h2>A. 2Pi</h2>
Step-by-step explanation:
The given function is

Notice that the indepedent variable doesn't have any transformation, that means the period doesn't change. In other words, this function has the same period than its parent function which is
.
Therefore, the answer is A.
The image attached shows the graph of this function, there you can observe the period of the function.
Also, notice that this function is verticall stretched by a scale of 2, which doesn't change its original period.