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abruzzese [7]
2 years ago
13

Use distributive property to calculate the following.

Mathematics
1 answer:
sattari [20]2 years ago
4 0

Answer:

Step-by-step explanation:

1. 2x + y

2. 48 +  60 = 108

3. 840 - 210 = 630

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4) The area of a piece of pie in the shape of a sector is 7.1 in. The angle of the sector is 40°. Find the diameter of
elixir [45]

Answer:

Step-by-step explanation:

Area of sector = angle/360 * pi * r^2

7.1 = 40/360 * 22/7 * r^2

7.1 = 1/9 * 22/7 * r^2

63.9 = 22r^2/7

r^2 = (7 * 63.9)/22

r^2 = 20.331818181818

r = square root of 20.331818181818

r = 4.51

d = r * 2 = 4.51 * 2 = 9.02

4 0
3 years ago
16.45 markdown 33% what’s the anwser
Fittoniya [83]

dude, use a calculator

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
Please help. Don’t understand this math problem!!!
Fittoniya [83]

Answer:

1). Option (C)

2). Option (A). degree of 3 = 0

Step-by-step explanation:

A polynomial having one term is called 'Monomial' in algebraic terms.

3 is a number that is a polynomial with a single term.

Therefore, the given expression is a polynomial.

Hence Option (C) is the answer.

3 can be written as 3x⁰ (Since x⁰ = 1)

Therefore, degree of the polynomial is 0.

Option (A). degree of the polynomial = 0

6 0
3 years ago
Consider the following function.
Kryger [21]

Answer:

See below

Step-by-step explanation:

I assume the function is f(x)=1+\frac{5}{x}-\frac{4}{x^2}

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, x=0 is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

f(x)=1+\frac{5}{x}-\frac{4}{x^2}

f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}

0=-\frac{5}{x^2}+\frac{8}{x^3}

0=-5x+8

5x=8

x=\frac{8}{5}

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}

f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3

Therefore, the function increases on the interval (0,\frac{8}{5}) and decreases on the interval (-\infty,0),(\frac{8}{5},\infty).

C) Since we determined that the slope is 0 when x=\frac{8}{5} from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}, meaning there's an extreme at the point (\frac{8}{5},\frac{41}{16}), but is it a maximum or minimum? To answer that, we will plug in x=\frac{8}{5} into the second derivative which is f''(x)=\frac{10}{x^3}-\frac{24}{x^4}. If f''(x)>0, then it's a minimum. If f''(x), then it's a maximum. If f''(x)=0, the test fails. So, f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}, which means (\frac{8}{5},\frac{41}{16}) is a local maximum.

D) Now set the second derivative equal to 0 and solve:

f''(x)=\frac{10}{x^3}-\frac{24}{x^4}

0=\frac{10}{x^3}-\frac{24}{x^4}

0=10x-24

-10x=-24

x=\frac{24}{10}

x=\frac{12}{5}

We then test where f''(x) is negative or positive by plugging in test values. I will use -1 and 3 to test this:

f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34, so the function is concave down on the interval (-\infty,0)\cup(0,\frac{12}{5})

f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0, so the function is concave up on the interval (\frac{12}{5},\infty)

The inflection point is where concavity changes, which can be determined by plugging in x=\frac{12}{5} into the original function, which would be f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}, or (\frac{12}{5},\frac{43}{18}).

E) See attached graph

5 0
3 years ago
The coefficient of 8.2 N is<br> 8<br> 2<br> 16
Aliun [14]

Answer:

2

Step-by-step explanation:

A coefficient is the number placed before the variable. The variable gets multiplied by the coefficient.

The format is not exactly clear with the expression in the question.

Assuming the expression is '8 * 2n', the coefficient would be 2.

'n' is getting multiplied by '2'.

'8' does not have a variable next to it, so it is just a term in the expression.

The product of 8 and 2 is 16. 16 is not in the expression.

If the expression was '8.2n', 8.2 would be the coefficient.

<em>Brainilest Appreciated. </em>

4 0
3 years ago
Read 2 more answers
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