Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Answer:
void delete_record(student_record *arr, int &size, int age, string name, double gpa) {
int index = -1;
if (arr != NULL && size > 0) {
for (int i = 0; i < size; ++i) {
if (arr[i].age == age && arr[i].name == name && arr[i].gpa == gpa) {
index = i;
break;
}
}
}
if (index != -1) {
for (int i = index; i < size - 1; ++i) {
arr[i] = arr[i + 1];
}
size--;
}
}
Image that a bit is the smallest measure in programming, such as an elementary particle in physics. So, a bit can only fit one number.
