The length of the side of an equilateral triangle that is circumscribed by a circle with radius r is s = r sqrt(3)so s = (6) sqrt(3)then the formula for the area of an equilateral triangle isA = sqrt(3) (s^2) / 4
substitute the value of s in the equationA = sqrt(3) ( (6) sqrt(3))^2 /4A = 46.77 sq in
Answer:
12.6 cm
Step-by-step explanation:
(other leg)² = (15)² - (8)²
(other leg)² = 225 - 64
other leg = √161 ≈ 12.6 cm
Answer:
d) 9 years
Step-by-step explanation:
let present age as 'x'.
then, x=2x-3(x-6)
x=2x-3x+18
x= -x+18
2x=18
x=18/2
x=9
Answer:
The ball is in the air for approximately 3.27 seconds ⇒ answer A
Step-by-step explanation:
* Lets explain how to solve the problem
- The height of the ball is modeled by the function
h(t) = -4.9 t² + 16 t
- We need to find the time that the ball is in the air
- The ball is in the air from its initial position and then return to the
same position
- That means h(t) = 0 because h(t) represent the height of the ball
from its initial position
∵ h(t) = -4.9 t² + 16 t
∵ h(t) = 0
∴ 0 = -4.9 t² + 16 t
- Add 4.9 t² to both sides
∴ 4.9 t² = 16 t
- Subtract 16 t from both sides
∴ 4.9 t² - 16 t = 0
- Take t as a common factor
∴ t (4.9 t - 16) = 0
- Equate each factor by 0
∴ t = 0 and 4.9 t - 16 = 0
∵ 4.9 t - 16 = 0 ⇒ add 16 for both sides
∴ 4.9 t = 16
- Divide both sides by 4.9
∴ t = 3.2653
∴ t = 0 ⇒ initial position
∴ t = 3.2653 seconds ⇒ final position
* <em>The ball is in the air for approximately 3.27 seconds</em>
