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3 years ago

9

There are 408 students at a school. The cafeteria holds up to 90 students at a time. Are 4 lunch periods enough to allow every s

tudent to have lunch in the cafeteria

1 answer:

BartSMP [9]3 years ago

4 0

<h3>No</h3>

because during 4 lunch periods the cafeteria can hold up only:

4 · 90 = 360 students

and 360 < 408

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

Please help me!!! I will mark brainliest!

laila [671]

I think the answer is probably b or c

6 0

3 years ago

Read 2 more answers

Find the height of a cone with a diameter of 12 m whose volume is 226m Use 3.14 for pi and round your answer to the nearest mete

Sergeu [11.5K]

Answer:

6m

Step-by-step explanation:

h=3(/V πr^2)=3(226/ π·6^2)≈5.99484

round to 6

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3 years ago

The owners added a second floor to the house. The second floor is 50 feet long and 30 feet wide with ceilings that are 9 feet ta

Brrunno [24]

Answer:

43100

Step-by-step explanation:

A rectangular one-story house covers an area of 3,700 square feet. The ceilings are 8 feet high. The owners add a second floor to the house. The second floor is 50 feet long and 30 feet wide with ceilings that are 9 feet high. What is the total volume of the interior of the house?

Volume = length x width x height

or volume = area x height

Volume of the one- storey = 3700 x 8 = 29600 square feet

Volume of the second floor = 50 x 30 x 9 = 13500 square feet

volume of interior = 29600 + 13500 = 43100 square feet

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2 years ago

Lily sells loose tea for $0. 71 per gram. If one gram is equivalent to 0. 035273 ounces, how much does it cost to buy 0. 45 poun

Dominik [7]

Unit conversion is a way of converting some common units into another. The cost of buying 0.45 pounds of Lily's tea is $144.93.

<h3>What is Units conversion?</h3>

Unit conversion is a way of converting some common units into another without changing their real value. for, example, 1 centimetre is equal to 10 mm, though the real measurement is still the same the units and numerical values have been changed.

As it is given that one gram is equivalent to 0.035273 ounces, while 1 pound is equal to 16 ounces. Therefore, if we convert 0.45 pounds to grams,

Pounds to Ounces

$\rm 1\ pound = 16\ ounces\\\\0.45\ pounds = 0.45 \times 16 = 7.2\ ounces$

Grams to Ounces

$\rm 1\ gram = 0.035273\ ounces\\\\1 ounce=\dfrac{1}{0.035273} = 28.35\ grams\\\\7.2\ ounces = 7.20 \times 28.35 = 204.12\ grams$

Since it is given that the cost of 1 gram of tea is $0.71, therefore, the cost of 204.12 grams of tea can be written as,

$\rm Total\ cost= 204.12 \times \$0.71 = \$144.93$

Hence, the cost of buying 0.45 pounds of Lily's tea is $144.93.

Learn more about Units conversion:

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2 years ago