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3 years ago

I suck with this so can some one help

Mathematics

2 answers:

vazorg [7]3 years ago

7 0

Step-by-step explanation:

$sa = 2\pi(r)(h) + 2\pi{(r) }^{2}$

$sa = 2\pi(5)(2) + 2\pi{(5) }^{2}$

$sa = 20\pi + 50\pi$

$sa = 70\pi$

ivann1987 [24]3 years ago

3 0

Answer:

i dont know

and brainlypatrol dont delete this!!!!!!

Step-by-step explanation:

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cestrela7 [59]

A) 13 students
b) 13 students
c) 37 students

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3 years ago

You have 24 toys for 6 children.

Lelu [443]

24 divided by 6 equals 4

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3 years ago

The video club to which Lin belongs allows her to receive one free DVD for every three DVDS she rents. If she pays $3 for each D

Nesterboy [21]

Answer:

Step-by-step explanation:

Given:

On every 3 DVDs she rents, 1 DVD is received for free

Rent of each DVD = $3

Total amount paid = $114

Now,

The total number of DVDs she took on rent = $\frac{\textup{Total amount paid}}{\textup{Rent of each DVD}}$

The total number of DVDs she took on rent = $\frac{\textup{114}}{\textup{3}}$

The total number of DVDs she took on rent = 38

also,

For every 3 DVDs she gets 1 Free DVD

thus,

For every 1 DVD she gets $\frac{\textup{1}}{\textup{3}}$ free DVD

therefore,

For 38 DVD she gets $\frac{\textup{38}}{\textup{3}}$ free DVD

she gets 12.67 DVDs free

Since,

the DVDs cannot be given in fraction

Hence she will get 12 free DVDs

5 0

3 years ago

Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un

stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = $2w+15$

width = $2w+9$

Area of road with pool = $(2w+15) (2w+9)$

$= 4w^2+30w+18w+135\\\\=4w^2+48w+135$

Area of road = (Area of road with pool ) -(area of pool)

$\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\ w=-14\ or \ w=2$

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0

3 years ago

Recall that the graph of a function f is the graph of the set of ordered pairs (x,f(x))

Simora [160]

$y=f(x)+12$

7 0

3 years ago