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Andrews [41]
3 years ago
11

I suck with this so can some one help

Mathematics
2 answers:
vazorg [7]3 years ago
7 0

Step-by-step explanation:

sa = 2\pi(r)(h) + 2\pi{(r) }^{2}

sa = 2\pi(5)(2) + 2\pi{(5) }^{2}

sa = 20\pi + 50\pi

sa = 70\pi

ivann1987 [24]3 years ago
3 0

Answer:

i dont know

and brainlypatrol dont delete this!!!!!!

Step-by-step explanation:

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A) 13 students
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You have 24 toys for 6 children.
Lelu [443]
24 divided by 6 equals 4
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The video club to which Lin belongs allows her to receive one free DVD for every three DVDS she rents. If she pays $3 for each D
Nesterboy [21]

Answer:

12

Step-by-step explanation:

Given:

On every 3 DVDs she rents, 1 DVD is received for free

Rent of each DVD = $3

Total amount paid = $114

Now,

The total number of DVDs she took on rent = \frac{\textup{Total amount paid}}{\textup{Rent of each DVD}}

or

The total number of DVDs she took on rent = \frac{\textup{114}}{\textup{3}}

or

The total number of DVDs she took on rent = 38

also,

For every 3 DVDs she gets 1 Free DVD

thus,

For every 1 DVD she gets \frac{\textup{1}}{\textup{3}} free DVD

therefore,

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the DVDs cannot be given in fraction

Hence she will get 12 free DVDs

5 0
3 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

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Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

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\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

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3 years ago
Recall that the graph of a function f is the graph of the set of ordered pairs (x,f(x))
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y=f(x)+12
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