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Oksi-84 [34.3K]
3 years ago
5

A test contains 40 questions Max's goal is to learn at least a 90 percent how many questions must he answer correctly to get at

least a 90% show work using equivalent fractions
Mathematics
1 answer:
Mice21 [21]3 years ago
6 0
90% = 90/100 

x/40=90/100  cross multiply 

100x = 3600 divide by 100 on both sides 
x=36 

Max needs to get at least 36 questions correct to earn a 90&
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A repeating pattern of figures that completely covers a plane, without gaps or overlaps, is called a _____ conjecture. transform
KonstantinChe [14]

Answer:A repeating pattern of figures that completely covers a plane, without gaps or overlaps, is called a<u> tessellation</u>.

Step-by-step explanation:

  • A tessellation of a flat surface is the tiling of a plane using one or more geometric shapes are called tiles, without overlaps or gaps.
  • They can be generalized to higher dimensions and a variety of geometries.

Therefore, A repeating pattern of figures that completely covers a plane, without gaps or overlaps, is called a<u> tessellation</u>.

3 0
2 years ago
The collection of all input values is the ___ of the function ?
hichkok12 [17]

Answer:

Domain

Step-by-step explanation:

Input Values Form the Domain of the Function

Mathematicians call the set of all input values for a function its domain.

3 0
2 years ago
A table and 8 chairs weigh 235.68 lb together. If the table weighs 157.84 lb, what is the weight of one chair in pounds?
Alona [7]

Answer: 9.73 lb each chair

Step-by-step explanation:

You substract the weight of the table alone from the full weight:

235.68 - 157.84=77.84

Then you divide 77.84 by 8 chairs and you obtain the weight of each individual chair

77.84/8= 9.73 the weight of each individual chair

7 0
3 years ago
Read 2 more answers
(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

Then the resulting ODE in v(x) is separable, with

1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx

On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

1-v^2=e^{2x+C}

v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
3 years ago
True or false
Nadusha1986 [10]

Step-by-step explanation:

2⁴×3²

2⁷

True

1⁰×0¹

1×0

0≠ 1

False

3⁴>4³

81>64

True

4⁰+5⁰+6⁰=(4+5+6)⁰

1+1+1=(15)⁰

3≠0

False

4 0
3 years ago
Read 2 more answers
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