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Oksi-84 [34.3K]
2 years ago
5

A test contains 40 questions Max's goal is to learn at least a 90 percent how many questions must he answer correctly to get at

least a 90% show work using equivalent fractions
Mathematics
1 answer:
Mice21 [21]2 years ago
6 0
90% = 90/100 

x/40=90/100  cross multiply 

100x = 3600 divide by 100 on both sides 
x=36 

Max needs to get at least 36 questions correct to earn a 90&
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-3r + 7 - 3r - 12 in simplest form
Akimi4 [234]
Since the co-efficient or "r" is "-3" and "-3", it will simplify to "-6" as -3-3= -6.
then the two constant terms with are "7" and "-12" will simplify to "-5" as 7-12=-5. therefore, the simplest form is -6r -5

hope it helped!
8 0
2 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
2 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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2x - 1 = 17...............
Alika [10]

Answer:

x = 9

Step-by-step explanation:

2x - 1 + 1 = 17 + 1

2x = 18

(2x=18)/2

x = 9

8 0
2 years ago
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If the discriminant of a quadratic equation is equal to -8 , which statement describes the roots?
GaryK [48]

Answer: There are no real number roots (the two roots are complex or imaginary)

The discriminant D = b^2 - 4ac tells us the nature of the roots for any quadratic in the form ax^2+bx+c = 0

There are three cases

  • If D < 0, then there are no real number roots and the roots are complex numbers.
  • If D = 0, then we have one real number root. The root is repeated twice so it's considered a double root. This root is rational if a,b,c are rational.
  • If D > 0, then we get two different real number roots. Each root is rational if D is a perfect square and a,b,c are rational.
3 0
3 years ago
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