I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
<span>x= -13 <span>± √169 + 192 / 4</span>
x= -13 </span>± √<span>361 / 4
The square root of 361 is 19.
So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2
x = -8, 3/2</span>
32/100 , sorry if it’s incorrect
Answer:
Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,
<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>
<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>
- If we have a logarithmic equation as ,
Then this can be written as ,
In a similar way we can write the given equation as ,
- Now also we know that Therefore , the equation becomes ,
<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>
Answer:
13
Step-by-step explanation:
The given expression is equal to 144 or
<em><u>Solution:</u></em>
Given expression is:
We have to evaluate the above given expression
We know that,
Substituting these in above given expression, we get
Also we know that,
Therefore,
Thus the given expression is equal to 144 or