Make an algebraic expression for each plan.
For an instance, x represents the number of movies, and y represents the number of months
⇒ The expression for the digital movie plan is 3x
⇒ The expression for the DVD plan is 10y + 0.5x
A person rents movies in a month (that means the value of y equals 1), the expression of the DVD plan would be 10(1) + 0.5x = 10 + 0.5x
Find the value of x when the cost of both plan are the same
The two options will cost the same when the expression for digital movie is equal to the expression for DVD
the digital movie plan = the DVD plan
3x = 10 + 0.5x
Solve for x
3x - 0.5x = 10
2.5x = 10
x = 10/2.5
x = 4
The two options will cost the same, if the person rents 4 movies
According to the graph, the answer is C. 150
Answer:
B) 378 students could be expected to attend the game.
Step-by-step explanation:
Out of 40 students, 45% agreed,
45% of 40
= 45/100 * 40
= 18 students,
18 students out of 40 agreed.
So, Out of 840 students 18/40 * 840 students would be expected to agree. We get :- 378
Answer: D. 12h + 21h2
Step-by-step explanation: The answer is D,
because when you devide 12h/3h = 4
and for the other value 21h2/3h=7h
4 + 7h
if you perform the same operation with the rest of answers you will get a minor values if you compare with this results, because of that the answer with the greatest common factor is D.
Answer:
2. ad is the angle bisector of angle a
3. ad is perpendicular to bc
4. both are right angles as given
5. common
6. ASA congruence
