√13= what does it equal

The density of the American white oak tree is 752 kilograms per cubic meter. If the trunk of an American white oak tree has a ci

iVinArrow [24]

Here I hope this helps you out

8 0

3 years ago

Read 2 more answers

Help!!! Please help me I need help on my homework!

Zina [86]

Answer:

B 4ab= c^2 - (b-a) ^2

Step-by-step explanation:

Hopefully this helps

6 0

3 years ago

30 points!! What is the sum of the first six terms of the series? 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

3 years ago

point f has coordinated (8,-1), point g is symmetric to point f with respect to the line y=x, what are the coordinates of point

Alex17521 [72]

If points f and g are symmetric with respect to the line y=x, then the line connecting f and g is perpendicular to y=x, and f and g are equidistant from y=x.

This problem could be solved graphically by graphing y=x and (8,-1). With a ruler, measure the perpendicular distance from y=x of (8,-1), and then plot point g that distance from y=x in the opposite direction. Read the coordinates of point g from the graph.

Alternatively, calculate the distance from y=x of (8,-1). As before, this distance is perpendicular to y=x and is measured along the line y= -x + b, where b is the vertical intercept of this line. What is b? y = -x + b must be satisfied by (8,-1): -1 = -8 + b, or b = 7. Then the line thru (8,-1) perpendicular to y=x is y = -x + 7. Where does this line intersect y = x?

y = x = y = -x + 7, or 2x = 7, or x = 3.5. Since y=x, the point of intersection of y=x and y= -x + 7 is (3.5, 3.5).

Use the distance formula to determine the distance between (3.5, 3.5) and (8, -1). This produces the answer to this question.

7 0

3 years ago

For tall heterozygotes with antennae, the offspring are:

Misha Larkins [42]

Recombinant frequency between T and A is 12%

Explanation:

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

Given:

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = $\frac{7}{100} + \frac{5}{100}$

Recombinant frequency = $\frac{12}{100}$

Recombinant frequency in percentage = $\frac{12}{100} X 100 = 12$ %

Therefore, recombinant frequency between T and A is 12%

8 0

3 years ago