<u>Bus:</u>
40 min = 36 miles
1 min = 36 ÷ 40 = 0.9 mile
<u>Car:</u>
1 min = 0.9 x 1.4 = 1.26 miles
<u>Total distance covered by both vehicles in 1 min: </u>
1.26 + 0.9 = 2.16 miles
<u>Time needed for both of them to cover 36km:</u>
36 ÷ 2.16 = 16 2/3 min
Answer: They will meet 16 2/3 mins after they have started.
In 14 minutes, Dan has already traveled 840 miles
14 • 60 = 840
Since Jake bikes 210 per minute, you would need to divide the total number of miles that Dan has traveled in 14 minutes (840 miles) by the amount of miles Jake can travel in one minute (210).
840 ÷ 210 = 4 minutes
Answer: 4 minutes
(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3
= a^4b^9/2a^8b^4
=b^5/2a^4
so your answer is b^5/2a^4
9 * x = 9x
9 * 5 = 45
9 * 8y = 40y
9x + 45 + 40y
9x + 40y + 45
Answer: Clearify
Step-by-step explanation:
