Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
24x-48y
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
80000
Step-by-step explanation:
Significant figures are any number but zeroes.
However, in some cases, zeroes also count as significant figures.
- Zeroes are significant figures when between other non-zero numbers.
- Zeroes are significant when you see a dot on the right indicating that zero is not a place holder.
- They are <u>not</u> significant when serving as place holders, such as zeroes on the right side of a number. For example, .004 has 1 sig fig. The 2 zeroes on the left aren't sig figs because they're just place holders.
- Zeroes on the <u>right</u> side of a decimal are also significant.
