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aniked [119]
3 years ago
14

HELPP

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0
Answer
A small class has five boys and six girls. A group of four students are to be selected at random to interview a new school director. a) Find the probability that the group contains at least one boy. b) Find the probability that the majority of the group is girls. c) Given that the group contains at least one boy, what is the chance that the boys are in the majority?
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An angle bisector of a triangle divides the opposite side of the triangle into segments 1.5 cm and 1 cm long. A second side of t
bagirrra123 [75]
By the angle bisector theorem, one of the lengths of the third side of the triangle is given by:
1.5 / 1 = x / 2.6
x = 1.5 x 2.6 = 3.9
One of the possible length of the third side is 3.9 cm

The other possible length is given by 1 / 1.5 = x / 2.6
1.5x = 2.6
x = 2.6/1.5 = 1.7
The other possible length of the third side is 1.7 cm.
4 0
3 years ago
Which is the better deal per car? 12 car washes for $100 or 5 car washes for $45
il63 [147K]

Answer:

12 Car washes for $100

Step-by-step explanation:

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5 0
3 years ago
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A thief who is particularly knowledgeable about statistics and the legal system determines that if he commits a given heist the
wolverine [178]

9514 1404 393

Answer:

  about 28.6%

Step-by-step explanation:

The conditional probability equation can be used:

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  = 0.24/0.84 = 2/7 ≈ 28.6%

3 0
2 years ago
I need some help with this math problem. I've had it explained to me two different ways. If x= -3 then what would be the answer
nadya68 [22]

Answer:

The square root of x will be evaluated first before the addition of 5. Hence (-3)^2 = 9 and 9 +5 = 14, as per your teacher's answer, which is correct. The answer would not be -4.

8 0
3 years ago
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HELP PLEASE!! HURRY!!!! NO SPAM!!!!!! Identify the solution set of the inequality 4|f + 6| ≤ −16 and the graph that represents i
blagie [28]

Answer: f=3

Step-by-step explanation:

The intervals means that angle f is between the quadrant 1.

where x+y=90

6 0
3 years ago
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