Lim x→0 (√(ax+b)-2)/x=1
You want to know the value of "a" and "b"
lim x→0 (√(ax+b)-2)/x=(√(0+b)-2)/0=(√b -2)/0;
Then if (√b -2)/0=1; the numerator must be "0"
(√b-2)=0
√b=2
(√b)²=2²
b=4
It is necessary the numerator must be "0", if the denominator is "0" and the result is equal a number.
Therefore:
lim (√(ax+4)-2)/x=1
x⇒0
I imagine you know Taylor Series.
√(ax+4)=(4(1+ax/4))¹/²=2(1+ax/4)¹/²
Remember:
(1/2)
(1+x)ᵃ=<span>Σ ( a ) x^a
</span>
In our case:
(1/2) (1/2) (1/2)
(1+ax/4)¹/²=( 0) (ax/4)⁰+( 1 ) (ax/4)¹+( 2) (ax/4)²+...
=1 +(1/2) ax/4 + -1/8 (ax/4)²+...
=1+ax/8-a²x²/128+...
Therefore:
lim (√(ax+4)-2)/x=lim [2(1+ax/8-a²x²/128+...)-2]/x=
x⇒0 x⇒0
lim [(2+ax/4-a²x²/64+...)-2]/x=
x⇒0
lim (ax/4-a²x²/64+...)/x=
x⇒0
lim x(a/4-a²x/64+...)/x=
x⇒0
lim (a/4-a²x/64+...)=(a/4-0-0-0-...)=4/a
x⇒0
Because:
lim (√(ax+4)-2)/x=1
x⇒0
Then:
4/a=1 ⇒ a=4
Answer: a=4; b=4
Answer:
y = 1
Step-by-step explanation:
I dunno what you need but that's the answer to y...
Answer:
C
Step-by-step explanation:
14 multiplied by 14 equals 196 which is closer to 14.0 than to 14.5
Isolate the x.
8x - 6 > 12 + 2x
Add 6 to both sides, and subtract 2x from both sides
8x (-2x) - 6 (+6) > 12 (+6) + 2x (-2x)
8x - 2x > 12 + 6
Simplify. Combine like terms
8x - 2x > 12 + 6
6x > 18
Isolate the x. Divide 6 from both sides
6x/6 > 18/6
x > 18/6
x > 3
Any number that is greater than 3 (3 not included), is your answer.
5 is your answer
hope this helps