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Alenkinab [10]
2 years ago
14

One line passes through the points (−1,6) and (2,0). A second line passes through the points (−5,5) and (−1,9). At what point do

the two lines intersect
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
7 0

Answer:

(-2,8)

Step-by-step explanation:

Slope m = (y2-y1)/(x2-x1)

Line 1: m = (0 - 6)/(2 - -1) = -6/3 = -2

y = mx+ b => y = -2x + b => 0 = -2(2) + b => 0 = -4 + b => b = 4

y = -2x + 4

Line 2: m = (9 - 5)/(-1 - -5) = 4/4 = 1

y = mx + b => y = x + b => 9 = -1 + b => b = 10

y = x + 10

When the 2 line intersects, they will same the same (x,y)

so line 1 = line 2

-2x + 4 = x + 10

-2x - x = 10 - 4

-3x = 6

x = -2

y = -2x + 4 = -2(-2) + 4 = 8

so the lines intersect at (-2,8)

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anzhelika [568]

Answer:

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Step-by-step explanation:

A linear pair is two angles which form a straight angle when combined (or 180 degrees). Thus do 180 - 113 to get 67 degrees for Angle 2

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Site A    y = $0.85x      =  $0.85(5)  =  $4.25
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We can see that Jim was paid $2.25 more at site A than Site B.
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Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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