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2 years ago

11

A shipment of 6 3/7 tons of sugar is separated into containers of equal size if the shipment fills 5 containers how much sugar c

an one container hold?

1 answer:

zlopas [31]2 years ago

8 0

Answer:

1 2/7 tons of sugar

Step-by-step explanation:

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If Carrie had 2 apples and Adam had 3, how many do they have altogether?

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0 bc u said had so they will have nothing left

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2 years ago

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Find the slope of the line through each pair of points.3) (3, -10), (14, -10)

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the second answer

Step-by-step explanation:

I took the test

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2 years ago

The height distribution of NBA players follows a normal distribution with a mean of 79 inches and standard deviation of 3.5 inch

Shtirlitz [24]

Answer:

The probability will be "0.0111".

Step-by-step explanation:

The given values are:

Mean,

$\mu$ = 79

Standard deviation,

$\sigma$ = 3.5

Now,

⇒ $\sigma\bar x = \frac{\sigma}{\sqrt n}$

$= \frac{3.5}{\sqrt 16}$

$=0.875$

⇒ $P(\bar x > 81) = 1 - P(\bar x < 81)$

So,

= $1 - P{\frac{(\bar x - \mu \bar x )}{ \sigma \bar x} < \frac{(81 - 79) }{0.875} ]$

= $1 - P(z < 2.2857)$

= $0.0111$

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3 years ago

3 − (2x − 5) < −4(x + 2)<br><br> please help!!!!!!!!!

Flauer [41]

Just plug in an easy number for "x" and solve. Then see if the second problem is really greater that the first

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3 years ago

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Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the

mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

$f(x)=Le^{-Lx}$

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

$f(x)=e^{-x}$

For a)

$P(T>2)$

$P(T>2)=1-P(T\leq 2)$

$P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx$

$P(T>2)=1-(-e^{-2}+1)$

$P(T>2)=e^{-2}=0.1353$

For b)

$P(T\geq 10/T>9)$

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

$P(T\geq 10/T>9)=P(T\geq 1)$

$P(T\geq 1)=1-P(T$

$P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679$

4 0

3 years ago