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Westkost [7]
2 years ago
11

A shipment of 6 3/7 tons of sugar is separated into containers of equal size if the shipment fills 5 containers how much sugar c

an one container hold?
Mathematics
1 answer:
zlopas [31]2 years ago
8 0

Answer:

1 2/7 tons of sugar

Step-by-step explanation:

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A ladder leaning against the side of a building touches the building at a point 12 meters from the ground. If the foot of the la
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I think the slope =21 m
i am not confirm if its not correct
6 0
3 years ago
Please help me ill mark you brainliest and please show your work :)
Nana76 [90]

Answer:

12

Step-by-step explanation:

Multiply both sides of the equation by 8/5.

4x-16=32

Move 16 to the other side

4x=32+16

add numbers on the right side

4x=48

divide both sides by 4

x=12

7 0
3 years ago
Can you help me with this Q i cant get it i have 3 min only please help me :)
Butoxors [25]

x= 3

AC = 22

hope it helps you...

7 0
3 years ago
Nancy also has a mirror that measures 20.32 centimeters long. What is the length of Nancy’s mirror in inches?
tino4ka555 [31]

Answer:

C: 8.00

Step-by-step explanation:

1 in = 2.54 cm

l = 20.32 × 1/2.54

l = 8.00 in

The length of Nancy’s mirror is 8.00 in.

3 0
3 years ago
A leprechaun places a magic penny under a​ girl's pillow. The next night there are 2 magic pennies under her pillow. The followi
Mars2501 [29]

Answer:

36 days

Step-by-step explanation:

Since the pennies need to be kept under the pillow in order to be doubled, we're really looking for the day the girl will wake up with 21 billions pennies under her pillow.

The general formula of that geometric sequence will be: t = 1 + 2^(n-1)

We need to find the value of n when t will be over 21,000,000,000.

So, the equation becomes:

21,000,000,001 = 1 + 2^(n-1)

2^(n-1) = 21,000,000,000

log(2^(n-1)) = log(21,000,000,000)

(n-1) * log(2) = log(21,000,000,000)

n-1 = log(21,000,000,000) / log(2)

n-1 = 34.29

n = 35.29

Since it has to be complete days, and we have to reach over 21 billions, then we round it up to 36.

5 0
3 years ago
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