81ft(yd/3ft)*111ft(yd/3ft)*2in(yd/36in)=55.5 yd^3
So 55 1/2 cubic yards of topsoil are needed.
Answer:
angle 2 = 90° {corresponding angles}
angle 7 + angle 5 = 180° {linear pair}
or, angle 7 + 100° = 180° {angle 5 is corresponding to 100°}
so, angle 7 = 80°
Answer:
78
Step-by-step explanation:
The IQR is quartile 3 - quartile 1. First, we need to find the mean of the dataset, which is 50 -- the fifth number. Then, the median of the dataset on the left of the fifth number is the first quartile, and the median of the dataset on the right is the third. We get Q1 to then be halfway between 30 and 50, or 40, and Q3 to be halfway between 56 and n, so Q3 = (56+n)/2. Since we need Q3-Q1=27, or (56+n)/2-40=27, we have (56+n)/2=67 and 56+n=134, so n = 134-56=78
No because They lose 12 sand that puts them at -12. Then they gain 5 which puts them at -7 and then they lose 8 which puts them at -15. Please mark as brainliest
Answer:
3.5x10^3
Step-by-step explanation:
3.5x10^2 = 350
350x10 = 3500
3500 = 3.5x10^3
