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DerKrebs [107]
2 years ago
6

HELP HOW AM I MEANT TO ANSWER THIS QUESTION I WOULD ASO LIKE ANSWER. THX

Mathematics
1 answer:
galina1969 [7]2 years ago
4 0
  • To find the number in a square, we have to multiply two circles which are connected to it.
  • So, to find a number in a circle, we have divide the number in the square by the number in the circle connected to it.
  • Therefore, -6 ÷ -3 = 2
  • 12 ÷ 2 = 6
  • 6 × -3 = -18

Please find the attached photograph for their positions.

Hope you could get an idea from here

Doubt clarification - use comment section.

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The graphs of f(x)=-2x and g(x)=(1/2)^x are shown. what are the solutions to thr equation -2x=(1/2)^x? select each correct answe
sineoko [7]

Answer:

<h2>-2</h2>

Step-by-step explanation:

hello :

f(x)=-2x and g(x)=(1/2)^x

f(-2)=-2(-2) =4

g(-2)=(1/2)^-2 = 1/2^-2 = 2²=4

4 0
3 years ago
Raquel is going on a vacation. She is trying to figure out how much money to bring along. She plans to spend $120 on hotels, $45
algol [13]

Answer:

$320

Step-by-step explanation:

she needs to take 320 dollars with her for the trip because she needs about 290 dollars for her expenses then she wants 30 dollars left over so she needs to take about 3320 dollars and none of that includes any tax.

hope this helps :)

3 0
4 years ago
Can you please explain and answer this question to me, (don't mind the blue dots, they are the answers of what I think, please l
Fofino [41]
I started with c, but you could’ve started with any box.

So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.

Then I went to a. All of a’s numbers were divisible by 7.

Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!

Then d. Two are divisible by 7, so your rules is divisible by 2.

I hope this helps!

6 0
3 years ago
Hi! What is 47 x 560? Please help
eduard

Answer:

26320

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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