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DerKrebs [107]
2 years ago
6

HELP HOW AM I MEANT TO ANSWER THIS QUESTION I WOULD ASO LIKE ANSWER. THX

Mathematics
1 answer:
galina1969 [7]2 years ago
4 0
  • To find the number in a square, we have to multiply two circles which are connected to it.
  • So, to find a number in a circle, we have divide the number in the square by the number in the circle connected to it.
  • Therefore, -6 ÷ -3 = 2
  • 12 ÷ 2 = 6
  • 6 × -3 = -18

Please find the attached photograph for their positions.

Hope you could get an idea from here

Doubt clarification - use comment section.

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Hong rented a truck for one day. There was a base fee of $20.95, and there was an additional charge of 90 cents for each mile dr
Goryan [66]

Answer: Hong drove the truck for 294 miles.

Step-by-step explanation:

Let m represent the number of miles for which he drove the truck.

There was a base fee of $20.95, and there was an additional charge of 90 cents for each mile driven. It means that the expression for the cost of driving the truck for m miles in a day is

20.95 + 0.9m

Hong had to pay $285.55 when he returned the truck. It means that

20.95 + 0.9m = 285.55

0.9m = 285.55 - 20.95

0.9m = 264.6

m = 264.6/0.9

m = 294 miles

5 0
3 years ago
What mathematical sentence is represented by the diagram?
cricket20 [7]
My only guess is a^2 + b^2 = c^2
7 0
3 years ago
HELPPPPPPPPPPPPPPPPPP
Finger [1]

Answer:

Given expression : \frac{9}{4}-2(4x+\frac{4}{3} )+\frac{5}{2}x    ......[1]

Using distributive property:  a\cdot (b+c) =a\cdot b + a\cdot c

[1]⇒   \frac{9}{4} - 2(4x) - 2(\frac{4}{3})+\frac{5}{2} x

Simplify:

\frac{9}{4} - 8x - \frac{8}{3}+\frac{5}{2}x

Like terms are those terms which are same variables.

Combine like terms: we get;

(\frac{9}{4} - \frac{8}{3}) - 8x + \frac{5}{2}x            ......[2]

\frac{27-32}{12} -8x +\frac{5}{2} x

Simplify:

\frac{-5}{12} -8x +\frac{5}{2}x  

or

\frac{-5}{12} - \frac{11}{2}x  

we can write equation [2] as;

\frac{27}{12} - \frac{8}{3} - 8x + \frac{5}{2}x

Combine like terms of x variables;

\frac{27}{12} - \frac{8}{3} - \frac{11}{2}x

Therefore, the expressions which are equivalent to the Given expression are:

\frac{9}{4} - 2(4x) - 2(\frac{4}{3})+\frac{5}{2} x

\frac{-5}{12} -8x +\frac{5}{2}x  

\frac{27}{12} - \frac{8}{3} - \frac{11}{2}x

\frac{-11}{2}x - \frac{5}{2}





3 0
3 years ago
Evaluate the expression for the given value of the variable -4b-8 + -1 b^2 + 2b^3 ; b= -2
Bad White [126]
-4b-8 + -1b^2 +2b^3
-4(-2)-8+-1(-2)^2+2(-2)^3
8-8+2^2-4^3
4-64
60
4 0
3 years ago
Read 2 more answers
Find the exact value of cos(7\pi /12)
Naya [18.7K]

7π/12 lies in the second quadrant, so we expect cos(7π/12) to be negative.

Recall that

\cos^2x=\dfrac{1+\cos(2x)}2

which tells us

\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1+\cos\left(\frac{7\pi}6\right)}2}

Now,

\cos\left(\dfrac{7\pi}6\right)=-\cos\left(\dfrac\pi6\right)=-\dfrac{\sqrt3}2

and so

\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1-\frac{\sqrt3}2}2}=\boxed{-\dfrac{\sqrt{2-\sqrt3}}2}

7 0
3 years ago
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