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Nostrana [21]
3 years ago
11

What is the value of this expression when c = -4 and d = 10?

Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0

Answer:

\Large \boxed{\mathrm{\bold{B. \ 9}}}

Step-by-step explanation:

Plug in c = -4 and d = 10 for the expression.

1/4(-4³ + 10²)

Evaluate the expression.

1/4(-64 + 100)

1/4(36)

36/4 = 9

denpristay [2]3 years ago
7 0

Answer:

\huge\boxed{B. \ \ 9}

Step-by-step explanation:

1/4 (c³ + d²)

Given that c = -4 and d = 10

1/4 ( -4³ + 10²)

1/4 ( -64+100)

1/4 ( 36 )

=> 9

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4 years ago
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Kipish [7]
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3 years ago
Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
3 years ago
Find the quotient.<br> 121.5 ÷ 9
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Answer:

13.5

Step-by-step explanation:

Entered in Calculator.

4 0
3 years ago
Read 2 more answers
What is the equation of the line that is perpendicular to the like y=-4x + 7 and passes through the point (8,2)?
Nookie1986 [14]

Answer:

y=\frac{1}{4}x

Step-by-step explanation:

Given equation of line:

y=-4x+7

To find the equation of line perpendicular to the line of the given equation and passes through point (8,2).

Applying slope relationship between perpendicular lines.

m_1=-\frac{1}{m_2}

where m_1 and m_2 are slopes of perpendicular lines.

For the given equation in the form y=mx+b the slope m_2can be found by comparing y=-4x+3 with standard form.

∴ m_2=-4

Thus slope of line perpendicular to this line m_1 would be given as:

m_1=-\frac{1}{-4}

∴ m_1=\frac{1}{4}

The line passes through point (8,2)

Using point slope form:

y_-y_1=m(x_-x_1)

Where (x_1,y_1)\rightarrow (8,2) and m=m_1=\frac{1}{4}

So,

y-2=\frac{1}{4}(x-8)

Using distribution.

y-2=(\frac{1}{4}x)-(\frac{1}{4}\times 8)

y-2=\frac{1}{4}x-2

Adding 2 to both sides.

y-2+2=\frac{1}{4}x-2+2

y=\frac{1}{4}x

Thus the equation of line in standard form is given by:

y=\frac{1}{4}x

6 0
3 years ago
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