Question

Need help on HS geometry

Answer 1

• Here, RY = PY.
• Angle QRY = Angle QPY = 90°
• QY = QY [common]
• Therefore, ∆ QRY = ∆ QPY
• By c.p.c.t., angle RQY = angle PQY
• Therefore,
• $16x - 27 = 5x + 6 \\ = > 16x - 5x = 6 + 27 \\ = > 11x = 33 \\ = > x = 3$
• Therefore, the measure of angle YQR
• $= (16x - 27)° \\ = (16 \times 3 - 27)° \\ = (48 - 27)° \\ = 21°$

Answers:

1. 3
2. 21°

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer 2

$\\ \tt\Rrightarrow 16x-27=5x+6$

$\\ \tt\Rrightarrow 16x-5x=6+27$

$\\ \tt\Rrightarrow 11x=33$

$\\ \tt\Rrightarrow x=3$

• m<YQR=16(3)-27=48-27=21°