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3 years ago

Need help on HS geometry

Mathematics

2 answers:

natita [175]3 years ago

8 0

Here, RY = PY.
Angle QRY = Angle QPY = 90°
QY = QY [common]
Therefore, ∆ QRY = ∆ QPY
By c.p.c.t., angle RQY = angle PQY
Therefore,
$16x - 27 = 5x + 6 \\ = > 16x - 5x = 6 + 27 \\ = > 11x = 33 \\ = > x = 3$
Therefore, the measure of angle YQR
$= (16x - 27)° \\ = (16 \times 3 - 27)° \\ = (48 - 27)° \\ = 21°$

<u>Answers:</u>

3
21°

Hope you could get an idea from here.

Doubt clarification - use comment section.

Illusion [34]3 years ago

6 0

$\\ \tt\Rrightarrow 16x-27=5x+6$

$\\ \tt\Rrightarrow 16x-5x=6+27$

$\\ \tt\Rrightarrow 11x=33$

$\\ \tt\Rrightarrow x=3$

m<YQR=16(3)-27=48-27=21°

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