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alexira [117]
3 years ago
9

Consider the following incomplete code segment, which is intended to increase the value of each digit in a String by one. For ex

ample, if num is 12345, then the resulting String would be 23456.
String num = "12345";
int counter = 0;
String result = "";
while(/* Missing Loop Header */)
{
int newNum = Integer.valueOf(num.substring(counter,counter+1));
result+= (newNum + 1);
counter++;
}
System.out.println(result);

Which of the following should replace /* Missing Loop Header */ so that the code segment works as intended?

counter < num.length() - 1


counter <= num.length()


counter < num.length()


counter > num.length()


counter < num.indexOf(counter)
Computers and Technology
1 answer:
arlik [135]3 years ago
7 0

The instruction that should replace /* Missing Loop Header */ so that the code segment works as intended is (c)  counter < num.length()

<h3>Loops</h3>

The program is an illustration of loops (the while loop)

While loops are program statements that are used to perform repeated operations

For the string to return 23456, the while loop body must be repeated as long the counter is less than the length of the string num

Hence, the missing loop header is counter < num.length()

Read more about loops at:

brainly.com/question/15683939

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Write a Python function check_subset() that takes in two Python lists, representing sets of integers, A and B. Your function sho
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Answer:

  1. def check_subset(l1, l2):
  2.    status = False
  3.    count = 0
  4.    if(len(l1) > len(l2)):
  5.        for x in l2:
  6.            for y in l1:
  7.                if x == y:
  8.                    count += 1
  9.        if(count == len(l2)):
  10.            return True  
  11.        else:
  12.            return False
  13.    else:
  14.        for x in l1:
  15.            for y in l2:
  16.                if x==y:
  17.                    count += 1
  18.        if(count == len(l1)):
  19.            return True  
  20.        else:
  21.            return False
  22. print(check_subset([1,4,6], [1,2,3,4,5,6]))
  23. print(check_subset([2,5,7,9,8], [7,8]))
  24. print(check_subset([1, 5, 7], [1,4,6,78,12]))

Explanation:

The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.

Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6).  If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.

The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)

If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:

True

True

False

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By this way, there won´t be any duplicated actions or reponses.

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