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blagie [28]
3 years ago
9

Solve this question with Statements and reasoning.

Mathematics
1 answer:
qaws [65]3 years ago
4 0

Here

\\ \sf\longmapsto PD\cong PC

As

P is the midpoint of AC and BD

\\ \sf\longmapsto AC=BD

\\ \sf\longmapsto AP+PC=PD+BP

  • Put PD=PC

\\ \sf\longmapsto AP+PC=PC+PB

  • Cancel PC

\\ \sf\longmapsto AP=BP(Proved)

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Answer:

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Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

  A = w(4w -15)

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b) If w is the side length, the area of the square is (also) the product of length and width:

  A = w²

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c) Equating the expressions for area, we have ...

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d) we can subtract the right side to get ...

  4w² -15w -w² = 0

  3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

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e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

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3 years ago
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Step-by-step explanation:

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Answer:

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