Answer:
Step-by-step explanation:
The mid point can be found with the formula
The given coordinates are 
and 
.
Replacing coordinates in the formula, we have
Therefore, the mid point of the segment PQ is
From the diagram given;
ABCD is a quadrilateral;
Line |EF| bisects the line |AD| and line |CD|,
Thus, from the given options;
LINE |EF| is a segment bisector is the only correct option.
Answer:
Those answers are correct that are shown and that are shown in blue
Step-by-step explanation:
Answer:
see below the first three problems
Step-by-step explanation:
f(g(-2))
First, find g(-2) using function g(x). Then use that value as input for function f(x).
g(x) = -2x + 1
g(-2) = -2(-2) + 1
g(-2) = 5
f(x) = 5x
f(5) = 5(5)
f(5) = 25
f(g(-2)) = 25
g(h(3))
First, find h(3) using function h(x). Then use that value as input for function g(x).
h(x) = x^2 + 6x + 8
h(3) = 3^2 + 6(3) + 8 = 9 + 18 + 8
h(3) = 35
g(x) = -2x + 1
g(35) = -2(35) + 1 = -70 + 1
g(35) = -69
g(h(3)) = -69
f(g(3a))
First, find g(3a) using function g(x). Then use that value as input for function f(x).
g(x) = -2x + 1
g(3a) = -2(3a) + 1
g(3a) = -6a + 1
f(x) = 5x
f(-6a + 1) = 5(-6a + 1)
f(-6a + 1) = -30a + 5
f(g(3a)) = -30a + 5
Answer:
f(x+5)=3x+16
Step-by-step explanation:
lets name " x+5" T
so f(T)=3T+1
now use "x+5" replace T
now its f(x+5)=3(x+5)+1=3x+15+1=3x+16
