Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides, 
and 
. A 95% large-sample CI for the true average percentage elongation is given by 
, i.e., 
or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
The surface area of the composite figure is; SA = 224 in.²
<h3>How to find the area of a Composite Figure?</h3>
From the composite figure attached, we can find the surface area of each of the rectangular/square external face seen as;
SA= 2(10 * 2) + 2(4 * 7) + 2(4 * 4) + 2(4 * 2) + (4 * 7) + (10 * 4) + (3 * 4)
SA = 40 + 56 + 32 + 16 + 28 + 40 + 12
SA = 224 in.²
Thus, we can conclude that the surface area of the composite figure is;
SA = 224 in.²
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The equation which represent the problem is 14.5 = 469.8k.
<h3>What is Equation?</h3>
An equation is a mathematical statement with an 'equal to =' symbol between two expressions that have equal values.
Here, As given in question
The number of gallons of gas Connie’s car, g, uses is directly proportional with the number of miles she drives, m.
g α m
g = km ............(i)
g = 14.5 gallons of gas m = 469.8 miles
14.5 = k X 469.8
14.5 = 469.8k
Thus, the equation which represent the problem is 14.5 = 469.8k.
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Answer: 0
First: Move constant to the left by adding its opposite to both sides
-3x+2y-7=7-7
Then: Change the signs on both sides of the equation
3x-2y+7
Equaling: 3x-2y+7=0
What is the image, i can’t see it?
